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irina1246 [14]
2 years ago
12

Is zach gay and a joe biden

Chemistry
1 answer:
shtirl [24]2 years ago
5 0

Answer:

yes they're gay

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Suppose these substance were placed in a freezer set to -50 grades celsius. Which substance would become a liquid. Clorine, Merc
Vadim26 [7]
Chlorine would become a liquid. Its boiling point is around -34 Celsius so at any temperature below that it would be liquid.
5 0
3 years ago
PLEASE HELP
dalvyx [7]

It has a -1 charge, so it would gain one!

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3 years ago
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To which period does an element belong if it has its 3d orbitals filled
kotegsom [21]

fourth period

The third period is similar to the second, except the 3s and 3p sublevels are being filled. Because the 3d sublevel does not fill until after the 4s sublevel, the fourth period contains 18 elements, due to the 10 additional electrons that can be accommodated by the 3d orbitals.

3 0
2 years ago
As the number of solute particles in a solution increases, the effect on the freezing point of the solution increases. Which ion
Ivahew [28]

Answer:

AlCl₃.

Explanation:

Adding solute to water causes depression of the boiling point.

The depression in freezing point (ΔTf) can be calculated using the relation:

ΔTf = i.Kf.m,

where, ΔTf is the depression in freezing point.

i is the van 't Hoff factor.

van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

Kf is the molal depression constant of water.

m is the molality of the solution (m = 1.0 m, for all solutions).

<u><em>(1) NaCl:</em></u>

i for NaCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (NaCl) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

<u><em>(2) MgCl₂:</em></u>

i for MgCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

∴ ΔTb for (MgCl₂) = i.Kb.m = (3)(Kf)(1.0 m) = 3(Kf).

<u><em>(3) NaCl:</em></u>

i for KBr = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (KBr) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

<u><em>(4) AlCl₃:</em></u>

i for AlCl₃ = no. of particles produced when the substance is dissolved/no. of original particle = 4/1 = 4.

∴ ΔTb for (CoCl₃) = i.Kb.m = (4)(Kf)(1.0 m) = 4(Kf).

  • So, the ionic compound will lower the freezing point the most is: AlCl₃.

3 0
3 years ago
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In a reaction between carbon monoxide and ferrous ferric oxide (Fe3O4), the theoretical yield in the experiment is calculated as
Naya [18.7K]

Answer:88.8%

Explanation:

%yield= actual yield/theoretical yield * 100/1

41.9/47.2*100/1= 88.8%

6 0
3 years ago
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