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____ [38]
3 years ago
13

During an experiment a student measured the temperature of water while it boiled in a pot on a stove. The temperature of the wat

er stayed at 100°C during the entire time that the water was boiling.
Chemistry
2 answers:
GalinKa [24]3 years ago
7 0

Answer:

The temperature of the water stayed at 100^{0} C because the temperature of a pure water does not increase at its boiling point, 100^{0} C. This is due to latent heat of vaporisation.

Explanation:

During a change of state of a substance, the temperature does not change due to latent heat of the substance. Latent heat is the amount of heat required to convert a unit mass of a substance from one state to another without a change in its temperature. There are two types of latent heat, latent heat of fusion anf latent heat of vaporisation.

So during the experiment, the water got to its boiling point and continues to boil at this constant temperature until it would change completely to steam at that temperature. After the conversion process, the temperature begins to increase.

The latent heat of vaporisation came into action during the process of boiling the water at constant temperature. That's why the temperature of the water did not increase even after reaching its boiling point (100^{0} C ).

Gemiola [76]3 years ago
5 0

Answer:

c,interpretation of the data

Explanation:

A good scientific explanation needs to be based on both data collected in an investigation and on the ability to interpret what the data means.

Normally, adding heat energy increases the temperature of a substance. However, during a phase change, the temperature of the substance stays constant. This happens because the heat energy is being used to change the phase of the matter instead of the temperature.

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Liquid nitrogen has a density of 0.808 g/mL and boils at 77 K. Researchers often purchase liquid nitrogen in insulated 185 L tan
Serga [27]

Answer:

37.14 %

Explanation:

Using the equation, mass, M = D1 * V1

= D2 * V2

Where,

D1 = density of the liquid Nitrogen

D2 = density of gaseous Nitrogen

V1 = volume of the liquid Nitrogen

V2 = volume of the gaseous Nitrogen

Calculating V2,

0.808 * 185 = 1.15 * V2

Volume of Nitrogen after expansion = 129.98 m3.

Volume = L * b * h

= 10 * 10 * 3.5

Volume of the room = 350 m3.

Fraction of air = volume of Nitrogen after expansion/volume of the room * 100

= 129.98/350 *100

= 37.14 %

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saul85 [17]

Answer:

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I hope this helps.
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