Answer:
A. from zero at the center to maximum at the circumference.
Explanation:
The shear stress describes the process where a body deforms as a result of a part sliding over the other.
The value of shear stress which is induced in the shaft due to the applied couple varies from zero at the center to maximum at the circumference.
The shear stress in a shaft is given by this formula;
τ = Tr/I
where;
τ = shear stress (MPa).
T = applied torque (Nmm).
r = distance from center to stressed surface in the given position (mm).
I = polar moment of Inertia of cross-sectional area (mm).
The Bidirectional Shift Register is the shift register that allows one to write a 5bit register if the series is shifted from left to right.
<h3>What is a value of a 5-bit register?</h3>
A 5-bit register is valuable because it can represent up to 32 items. It is to be noted that a bit is a digit that is binary that is indicative of two states.
While a 5-bit register can have a possible number of 32 values,
- 6 can hold 64;
- 7 can hold 128;
- 8 can hold 256 etc.
Learn more about registers at;
brainly.com/question/19091159
#SPJ1
Answer:
The solution code is written in Python:
- def convertCSV(number_list):
- str_list = []
- for num in number_list:
- str_list.append(str(num))
-
- return ",".join(str_list)
- result = convertCSV([22,33,44])
- print(result)
Explanation:
Firstly, create a function "convertCSV" with one parameter "number_list". (Line 1)
Next, create an empty list and assign it to a new variable <em>str_list</em>. (Line 2)
Use for-loop to iterate through all the number in the <em>number_list</em>.(Line 4). Within the loop, each number is converted to a string using the Python built-in function <em>str() </em>and then use the list append method to add the string version of the number to <em>str_list</em>.
Use Python string<em> join() </em>method to join all the elements in the str_list as a single string. The "," is used as a separator between the elements (Line 7) . At the end return the string as an output.
We can test the function by calling the function and passing [22,33,34] as an argument and we shall see "22,33,44" is printed as an output. (Line 9 - 10)
Answer:
R = 31.9 x 10^(6) At/Wb
So option A is correct
Explanation:
Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A
Thus; R = L/μA,
Now from the question,
L = 4m
r_1 = 1.75cm = 0.0175m
r_2 = 2.2cm = 0.022m
So Area will be A_2 - A_1
Thus = π(r_2)² - π(r_1)²
A = π(0.0225)² - π(0.0175)²
A = π[0.0002]
A = 6.28 x 10^(-4) m²
We are given that;
L = 4m
μ_steel = 2 x 10^(-4) Wb/At - m
Thus, reluctance is calculated as;
R = 4/(2 x 10^(-4) x 6.28x 10^(-4))
R = 0.319 x 10^(8) At/Wb
R = 31.9 x 10^(6) At/Wb
