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olasank [31]
3 years ago
13

Briefly discuss the principle forms of communication that might be utilized in the construction industry?

Engineering
1 answer:
e-lub [12.9K]3 years ago
4 0

Answer:

xcvjchjcnjkkhjmklk heyyyy biiiiiiiittcccchhh

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After replacing a vacuum booster, the brakes lock up on a road test. Technician A says there is air trapped inside the brake lin
vitfil [10]

Answer:

Technician B

Explanation:

The brakes can lockup due to the following reasons

1) Overheating break systems

2) Use of wrong brake fluid

3) Broken or damaged drum brake backing plates, rotors, or calipers

4) A defective ABS part, or a defective parking mechanism or proportioning valve

5) Brake wheel cylinders, worn off

6) Misaligned power brake booster component

5 0
3 years ago
if two or more resistors are connected in parallel, the total resistance is _ than any single resistor
Andreas93 [3]
Parallel Resistor Equation
If the two resistances or impedances in parallel are equal and of the same value, then the total or equivalent resistance, RT is equal to half the value of one resistor. That is equal to R/2 and for three equal resistors in parallel, R/3, etc.
7 0
3 years ago
When driving during the daytime in reduced visibility, such as rain, smoke, or fog,
riadik2000 [5.3K]

Answer:A

Explanation:

3 0
3 years ago
How much calcium chloride will react with100mg of soda ash?
mixer [17]

Answer:

105mg of calcium chloride CaCl_{2}

Explanation:

The molecular formula of calcium chloride is CaCl_{2} and the molecular formula of soda ash is Na_{2}CO_{3}

First of all you should write the balanced reaction between both compounds, so:

CaCl_{2}+Na_{2}CO_{3}=2NaCl+CaCO_{3}

Then you should have the molar mass of the two compounds:

Molar mass of CaCl_{2}=110.98\frac{g}{mol}

Molar mass of Na_{2}CO_{3}=105.98\frac{g}{mol}

Now with stoichiometry you can find the mass of calcium chloride that reacts with 100mg of soda ash, so:

100mgNa_{2}CO_{3}*\frac{1molNa_{2}CO_{3}}{105.98gNa_{2}CO_{3}}*\frac{1molCaCl_{2}}{1molNa_{2}CO_{3}}*\frac{110.98gCaCl_{2}}{1molCaCl_{2}}=105mgCaCl_{2}

6 0
4 years ago
John read the first 114114114 pages of a novel, which was 333 pages less than \dfrac13 3 1 ​ start fraction, 1, divided by, 3, e
sineoko [7]

Question:

John read the first 114 pages of a novel, which was 3 pages less than ⅓ of the novel. Write an equation to determine the total number of pages (P)

Answer:

114 = ⅓P - 3

Explanation:

Given

Number of pages read = 114

Total pages in novel = p

The relationship between the pages read by John and the total pages is analysed as follows:

3 less than ⅓ of total pages means:

⅓ of total pages - 3

Recall that P represents the total pages in the novel

So, the expression becomes

⅓ * P - 3

⅓P - 3

This means that the pages read by John is ⅓P - 3

This implies that the equation to determine the number of pages in the novel is

⅓P - 3 = 114

Solving further to get the actual number of pages;

Multiply both sides by 3

3(⅓P - 3) = 114 * 3

3 * ⅓P - 3 * 3 = 114 * 3

P - 9 = 342

Add 9 to both sides

P - 9 + 9 = 342 + 9

P = 351

Hence the number of pages is 351

8 0
4 years ago
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