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Harman [31]
3 years ago
13

How much force is needed to accelerate a 66 kg skier at 2 m/sec^2?

Physics
1 answer:
Ymorist [56]3 years ago
5 0
The equation of force is M(mass)•A(acceleration)=132N
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Help please help! Need help
Alborosie

Answer:

M. Magnetism is a property of individual atoms.

Explanation:

when a magnet is broken into pieces the new pieces behave like the original magnet this observation shows that magnetism is the property of individual atoms.

7 0
2 years ago
A man throws a ball straight up to his friend on a balcony who catches it at its highest point. The ball was thrown with an init
Ede4ka [16]

Answer:

The maximum height reached by the ball is 16.35 m.

Explanation:

Given;

initial velocity of the ball, u = 17.9 m/s

the final velocity of the ball at the maximum height, v = 0

The maximum height reached by the ball is given by;

v² = u² + 2gh

During upward motion, gravity is negative

v² = u² + 2(-g)h

v² = u² -  2gh

0 = u² -  2gh

2gh = u²

h = u² / 2g

h = (17.9)² / (2 x 9.8)

h = 16.35 m

Ttherefore, the maximum height reached by the ball is 16.35 m.

3 0
3 years ago
if we ignore air resistance the mass of an object does not affect the rate at which it accelerate why?​
quester [9]

Answer:

See explanation

Explanation:

The acceleration due to gravity on an object is independent of the mass of the object. This is so because, the acceleration due to gravity depends only on the radius of the earth and the mass of the earth.

As a result of this, all objects are accelerated to the same extent and should reach the ground at the same time when released from a height as long as other forces other than gravity are not at work.

5 0
3 years ago
A soccer player icks a rock horizontally off a 40m high cliff into a pool f water if the player hears the sound of the splash s
Semenov [28]

Answer:

v = 9.936 m/s

Explanation:

given,

height of cliff = 40 m

speed of sound = 343 m/s

assuming that time to reach the sound to the player = 3 s

now,

time taken to fall of ball

t = \sqrt{\dfrac{2s}{g}}

t = \sqrt{\dfrac{2\times 40}{9.8}}

t = 2.857 s

distance

d = v  x t

d = v x 2.875

time traveled by the sound before reaching the player

t_0 = t - t_{fall}

t_0 = 3 - 2.875

t_0 = 0.143 s

distance traveled by the wave in this time'

r = 0.143 x 343

r= 49.05 m

now,

we know.

d² + h² = r²

d² + 40² = 49.05²

d =28.387 m

v x 2.875=28.387 m

v = 9.936 m/s

7 0
3 years ago
When the distance between two interacting objects doubles, the gravitational force is
Umnica [9.8K]

The gravitational force will be one quarter.

The gravitational force between two objects is given by the formula

F=GMm/r^2

here, r is the distance between the objects.

Thus the gravitational force is inversely proportional to the square of the distance between the objects, Therefore if the distance between two objects is doubled the force will be one quarter.

5 0
3 years ago
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