Answer:
Neither side is favored
Explanation:
In a reaction at equilibrium in which reactants and products are gases, pressure is a factor that produces a shift of the equilibrium position. When the pressure is increased, the equilibrium is shifted to the side of the reaction with a fewer moles. In this reaction:
2 HD(g) ⇀↽ H₂(g) + D₂(g)
There is the same number of moles on both sides:
reactants side: 2 moles HD
products side: 1 mol H₂ + 1 mol D₂ = 2 moles
Therefore, the equilibrium position will not change.
Producers would not have enough nutrients .
Explanation:
1 mole of a gas has 22.4 L of volume at STP. Therefore, 0.5 mol of H2 has 0.5 x 6.022 x 1023 = 3.011 x 1023 molecules. Hence, the number of moles, molecules and atoms present in 11.2 liters of H2 at STP are 0.5 , 3.011 x 1023 and 6.022 x 1023 respectively.
Answer:
- 0.36 m/s.
Explanation:
- For the reaction: <em>a + 2b → c,</em>
<em>∵ The initial rate of the reaction = - δ[a]/δt = - 1/2 δ[b]/dt = 0.180 m/s.</em>
∴ The initial rate of the reaction = - 1/2 δ[b]/dt = 0.180 m/s.
∴ - 1/2 δ[b]/dt = 0.180 m/s.
<em>∴ δ[b]/dt </em>= (- 2)(0.180 m/s) =<em> - 0.36 m/s.</em>
