Answer:
4.68x10⁹
Explanation:
Kp is the equilibrium constant based on presure, and depends only on the gas substances. For a generic equation:
aA(g) + bB(g) ⇄ cC(g) + dD(g)
The reaction given can be summed to form the third one:
C(s) + CO₂(g) ⇄ 2CO (g) K'p = 1.30x10¹⁴
CO(g) + Cl₂(g) ⇄ COCl₂ (g) K''p = 6.00x10⁻³
We need to multiply the second reaction by 2, so CO will be simplified. If we multiplied a reaction for n, the new Kp will be (Kp)ⁿ, so:
C(s) + CO₂(g) ⇄ 2CO (g) K'p = 1.30x10¹⁴
2CO(g) + 2Cl₂(g) ⇄ 2COCl₂(g) (K''p)²= (6.00x10⁻³)²
The Kp of the reaction resulted by the sum will be: Kp = K'p*K''p
C(s) + CO₂(g) + 2Cl₂(g) ⇄ 2CO(g) + 2COCl₂(g)
Kp = 1.30x10¹⁴ * (6.00x10⁻³)²
Kp = 1.30x10¹⁴*3.60x10⁻⁵
Kp = 4.68x10⁹
Answer:
a metal
Explanation:
metals are good conductors of electricity.
Answer:
11
Explanation:
electronic configuration = 1s^2, 2s^2, 2p^6, 3s^1
therefore total electrons = 2+2+6+1 = 11
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We are given that the balanced chemical reaction is:
cacl2⋅2h2o(aq) +
k2c2o4⋅h2o(aq) --->
cac2o4⋅h2o(s) +
2kcl(aq) + 2h2o(l)
We known that
the product was oven dried, therefore the mass of 0.333 g pertains only to that
of the substance cac2o4⋅h2o(s). So what we will do first is to convert this
into moles by dividing the mass with the molar mass. The molar mass of cac2o4⋅h2o(s) is
molar mass of cac2o4 plus the
molar mass of h2o.
molar mass cac2o4⋅h2o(s) = 128.10
+ 18 = 146.10 g /mole
moles cac2o4⋅h2o(s) =
0.333 / 146.10 = 2.28 x 10^-3 moles
Looking at
the balanced chemical reaction, the ratio of cac2o4⋅h2o(s) and k2c2o4⋅h2o(aq) is
1:1, therefore:
moles k2c2o4⋅h2o(aq) = 2.28
x 10^-3 moles
Converting
this to mass:
mass k2c2o4⋅h2o(aq) = 2.28
x 10^-3 moles (184.24 g /mol) = 0.419931006 g
Therefore:
The mass of k2c2o4⋅<span>h2o(aq) in
the salt mixture is about 0.420 g</span>
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