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saw5 [17]
1 year ago
14

The weight of air in a column 1-m2 in cross section that extends from sea level to the top of the atmosphere is?

Physics
1 answer:
Sauron [17]1 year ago
3 0

From sea level to the top of the atmosphere, a column of air with a 1-m2 cross section weighs 101,000 N.

To find the answer we have to know about the pressure.

<h3>What is Pressure?</h3>
  • The pressure at a point on a surface is the thrust acting per unit area around that point.

                    Pressure, P=\frac{Thrust}{Area}=\frac{F}{A}

  • A particular mass of air is contained in a column that rises from the ocean to the top of the atmosphere. Then,

                   P=P_a=1.013*10^5 pascal

Pa is the atmospheric pressure at the sea level.

  • By combining both the equations, we get the weight of air,

                                       \frac{F}{A}=P_a

              F=W=P_a*A=1.013*10^5*1=101300N

Thus, we can conclude that, the weight of air in a column 1-m2 in cross section that extends from sea level to the top of the atmosphere is 101300N.

Learn more about the pressure here:

brainly.com/question/24818722

#SPJ4

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3 years ago
A permanent magnet has a magnetic dipole moment of 0.160 A · m^2. The magnet is in the presence of an external uniform magnetic
Elena L [17]

Answer:

the magnitude of the torque  on the permanent magnet = 7.34×10⁻³ Nm

the potential energy (in J) of the system consisting of the permanent magnet and the magnetic field provided by the coils =  -1.0485 ×10⁻² J

Explanation:

The torque is given by :

\bar {N} = \bar {m} * \bar {B}

where ;

m = 0.160 A.m²

B = 0.0800 T

θ = 35°

So the magnitude of the torque N = mBsinθ

N = (0.160)(0.0800)(sin 35°)

N = 0.007341

N = 7.34×10⁻³ Nm

Hence, the magnitude of the torque  on the permanent magnet = 7.34×10⁻³ Nm

b) The potential energy \bar{U} = \bar{-m} * \bar{B}

U = -mBcosθ

U = (- 0.160)(0.0800)(cos 45)

U = -0.010485

U = -1.0485 ×10⁻² J

Thus, the potential energy (in J) of the system consisting of the permanent magnet and the magnetic field provided by the coils =  -1.0485 ×10⁻² J

6 0
3 years ago
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Answer:

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Explanation:

Given that,

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Final position of the ball,  X₂ = -25 m

Time taken to travel is, t = 2.5 s

The average velocity of the ball is given by the formula,

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Substituting the values in the above equation,

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The negative sign in the velocity indicates that ball rolls in the opposite direction.

Hence, the average velocity of the ball is  v = -14 m/s

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