We can use the ideal gas law PV=nRT For the first phase The starting temperature (T1) is 273.15K (0C). n is 1 mole, R is a constant, P = 1 atm, V1 is unknown. The end temperature (T2) is unknown, n= 1 mol, R is a constant, P = 3*P1= 3 atm, V2=V1 Since n, R, and V will be constant between the two conditions: P1/T1=P2/T2 or T2= (P2*T1)/(P1) so T2= (3 atm*273.15K)/(1 atm)= 3*273.15= 816.45K For the second phase: Only the temperature and volume change while n, P, and R are constant between the start and finish. So: V1/T1=V2/T2 While we don't know the initial volume, we know that V2=2*V1 and T1=816.45K So T2=(V2*T1)/V1= (2*V1*T1)/V1=2*T1= 2*816.45K= 1638.9K To find the total heat added to the gas you need to subtract the original amount of heat so 1638.9K-273.15K= 1365.75K

6 0

3 years ago

Geraniol, C10H17OH, is an rose-scented alcohol commonly used in perfumes. How many grams of geraniol should be added to 600. mL

Maksim231197 [3]

Answer:

215.12 g

Explanation:

The change in the bolling temperature is a collateral property called ebullioscopy. The elevation on temperature occurs because there'll be a solute in the pure compound, and that solute(generally non-volatile) has a different boiling point, so the total bolling pint should increase.

To calculate the elevation in the temperature, we must use the Raoult equation:

ΔT = KbxWxi

Where ΔT is the variation of the temperature of boiling point, Kb is the

ebullioscopy constant, W is the molarity, and i the Vant' Hoff factor, which for molecules is also equal to 1, because they don't form ions. So:

82.00 - 78.40 = 1.22xW

W = 3.60/1.22

W = 2.9508

The molarity can also be calculated by:

$W = \frac{m1}{M1xm2}$

Where m1 is the mass of the solute (in grames), M1 is the molar mass of the solute, and m2 is the mass of the solvent (in kg).

The density of ethanol is 0.789 g/cm³, and 1 mL = 1 cm³, so 600.00 mL = 600.00 cm³ :

0.789 = m2/600

m2 = 473.4 g = 0.4734 kg

The molar mass of geraniol is:

C: 12 g/mol x 10 = 120 g/mol

H: 1 g/mol x 18 = 18 g/mol

O: 16 g/mol x 1 = 16 g/mol

M1 = 154 g/mol

Then:

$2.9508 = \frac{m1}{154x0.4734}$

m1 = 215.12 g of geraniol.

7 0

4 years ago