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Verdich [7]
3 years ago
9

How would you graph/sketch 40 lbs at pi/3 south of west

Physics
1 answer:
irinina [24]3 years ago
7 0
Well, pi/3 in Radians is equal to 60 degrees, and if your South is negative y and West is negative x, your line segment will be 60 degrees down of left, if you will. Your question is a little confusing, but I'm assuming you're drawing a force diagram, so probably draw the line segment at that angle and label it with the force of gravity- 40 lbs Hope that helps.
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The #1 answer would be meats and eggs. But, as a veggan, I present you with meatless protien-rich food!

1 - <u>Pea protein</u> (used in Beyond Meat, which tastes just like meat btw!)

2 - <u>Soy protein</u> such as tofu

3 - <u>Nuts</u>

4 - <u>Beans</u>! oml so many beans have MORE protien than meat!! ikr!?!?

may I have Brainliest pls =)

8 0
3 years ago
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il63 [147K]

Explanation:

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5 0
2 years ago
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Standing still, Bruce, the quarterback, gets tackled by Biff, the 90.0-kg tackle, who is traveling at 7.0 m/s. Upon collision, B
tatyana61 [14]

\\ \sf\longmapsto \Delta P=P

\\ \sf\longmapsto m1v1=m2v2

\\ \sf\longmapsto 90(7)=m2(10)

\\ \sf\longmapsto 10m2=630

\\ \sf\longmapsto m2=\dfrac{630}{10}

\\ \sf\longmapsto m2=63kg

Bruces mass is 63kg

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3 years ago
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What is meant by critical angle of indence?​
drek231 [11]
An angle of refraction of 90-degrees
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3 years ago
2.- Si una cámara fotográfica emite un pulso de sonido para enfocar un objeto, determinar
uranmaximum [27]

Answer:

a. El tiempo de recorrido es 5.882\times 10^{-3} segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

b. El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

Explanation:

El sonido es un tipo de onda mecánica, que es un tipo de onda que necesita de un medio material para propagarse. En este caso, entendemos que el sonido se propaga a través del aire atmosférico hasta llegar a su destino y devolverse a rapidez constante. Entonces, podemos estimar el tiempo (t), medido en segundos, a partir de la siguiente fórmula:

t = \frac{2\cdot x_{s}}{v_{s}}

Donde:

x_{s} - Distancia entre la cámara fotográfica y el objeto, medida en metros.

v_{s} - Rapidez del sonido en el aire atmosférico, medida en metros por segundo.

A continuación, calculamos el tiempo de recorrido:

a. (x_{s} = 1\,m, v_{s} = 340\,\frac{m}{s})

t = \frac{2\cdot (1\,m)}{340\,\frac{m}{s} }

t = 5.882\times 10^{-3}\,s

El tiempo de recorrido es 5.882\times 10^{-3} segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

b. (x_{s} = 20\,m, v_{s} = 340\,\frac{m}{s})

t = \frac{2\cdot (20\,m)}{340\,\frac{m}{s} }

t = 0.118\,s

El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

8 0
3 years ago
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