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murzikaleks [220]
3 years ago
10

According to Newton's 3rd Law of Motion, Doug, a baseball

Physics
1 answer:
sweet-ann [11.9K]3 years ago
6 0
B,
the reaction according to Newton’s third law must be an equal and opposite reaction. The force will be greater in order to bounce off of Doug’s bat
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What is the sequence of energy transformations associated with a hydroelectric dam?
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Gravitational potential energy -> Kinetic energy -> Mechanical energy -> Electrical energy.

The water starts up (potential) and flows down (kinetic), the flowing water turns a big wheel (mechanical) which creates electricity (electrical).

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A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 35.0 min
Lubov Fominskaja [6]

Explanation:

Solution:

Let the time be

t1=35min = 0.58min

t2=10min=0.166min

t3=45min= 0.75min

t4=35min= 0.58min

let the velocities be

v1=100km/h

v2=55km/h

v3=35km/h

a. Determine the average speed for the trip. km/h

first we have to solve for the distance

S=s1+s2+s3

S= v1t1+v2t2+v3t3

S= 100*0.58+55*0.166+35*0.75

S=58+9.13+26.25

S=93.38km

V=S/t1+t2+t3+t4

V=93.38/0.58+0.166+0.75+0.58

V=93.38/2.076

V=44.98km/h

b. the distance is 93.38km

6 0
3 years ago
1 determine the maximum force p the connection can support so that no slipping occurs between the plates. there are four bolts u
grigory [225]
The maximum force is 6.4 KN. Check the attached file for the explanation.

4 0
3 years ago
A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/
KatRina [158]

Complete Question

A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/h, 18.0 min at 80.0 km/h, and 60.0 min at 60.0 km/h and spends

25.0 min eating lunch and buying gas

What is the total distance traveled over the entire trip (in km)

Answer:

The value is D = 139.02 \ km

Explanation:

From the question we are told that

For t_1 =  55 min = \frac{55}{60}  =  0.917 \ h the speed is v_1 =  60 \  km/h

For t_2 =  18 min  = \frac{18}{60}  =  0.3 \ h the speed is v_2 =  80 \  km/h

For t_3 = 60 min = \frac{60}{60}  =  1 \ h the speed is v_3 =  60\  km/h

The time taken to have lunch is t _l  = 25 \  min =  \frac{25}{60} =  0.42 \  h

Generally the total distance traveled over the entire trip (in km) is mathematically represented as

D = t_1 *  v_1 + t_2 * v_2 + t_3 * v_3

=>   D = 0.917  *  60 +  0.3 * 80 +  1  * 60

=>   D = 55.02  + 24 +   60

=>   D = 139.02 \ km

4 0
3 years ago
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