Complete question is:
A 1200 kg car reaches the top of a 100 m high hill at A with a speed vA. What is the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 m/s. Neglect friction.
Answer:
(V_A) = 31.32 m/s
Explanation:
We are given;
car's mass, m = 1200 kg
h_A = 100 m
h_B = 150 m
v_B = 0 m/s
From law of conservation of energy,
the distance from point A to B is;
h = 150m - 100 m = 50 m
From Newton's equations of motion;
v² = u² + 2gh
Thus;
(V_B)² = (V_A)² + (-2gh)
(negative next to g because it's going against gravity)
Thus;
(V_B)² = (V_A)² - (2gh)
Plugging in the relevant values;
0² = (V_A)² - 2(9.81 × 50)
(V_A) = √981
(V_A) = 31.32 m/s
The difference between an sa and sb galaxy is Sa has a larger nucleus and more tightly wound arms than an Sb.
<h3>What is sa Galaxy?</h3>
Sa galaxies are normal spirals that have narrow, tightly wound arms, which usually are visible because of the presence of interstellar dust and, in many cases, bright stars.
<h3>What is sb Galaxy?</h3>
The arms of sb galaxy are more widely spread than those of the Sa variety and appear less smooth.
Thus, the difference between an sa and sb galaxy is Sa has a larger nucleus and more tightly wound arms than an Sb.
Learn more about sa galaxy here: brainly.com/question/9813915
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A). Her distance traveled was (700m + 500m) = <em>1,200 meters</em>
B). Her displacement was (700m north + 500m south) = <em>200 meters north</em>
C). Her average speed = (distance covered) / (time to cover the distance)
Speed = (1,200 meters) / (15 seconds)
<em>Speed = 80 meters/second</em>
(Layne is an incredible walker ! That's about 179 miles per hour.)
(She walks 700m in 10 seconds. Usain Bolt runs only 100m in 10 seconds.)
D). Her averge velocity = (displacement) / (time)
Velocity = (200 meters north) / (15 seconds)
<em>Velocity = (13 and 1/3) m/s north</em>
(This is only about 33% faster than Usain Bolt, if he went straight instead of doubling back, and if he could keep it up for 200 meters instead of only 100 meters.)
The weight of an object is the
force with which it is attracted to earth. The gravity of an object or body of
an object is high on earth than at the atmosphere. It has an average of
gravitational constant equal to 9.8066 or 9.8 meters per second. In truth, the acceleration
of the object depend upon its location, the latitude and altitude, on
earth.
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Answer:
Victor will always be able to select 4 of those cards with the following property
Explanation:
Number of trading cards = 100
victor selects 21 cards
let the 4 cards be labelled : A,B,C and D
The average power level of : A,B,C,D = ( A + B + C + D )/ 4 = P
let the two pairs be : ( A + B ) and ( C + D )
note: average power of each pair = P and this shows that
( A + B ) = ( C + D ) for Victor to select 4 cards out of the 21 cards that exhibit the same property
we have to check out the possible choices of two cards out of 21 cards yield distinct sums.
= C(21,2)=(21x20)/2 = 210.
from the question the number of distinct sums that can be created using 101 through 200 is < 210 .
hence it is impossible to get 210 distinct sums therefore Victor will always be able to select 4 of those cards
