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3 years ago

According to Newton's 3rd Law of Motion, Doug, a baseball

1 answer:

6 0

B,
the reaction according to Newton’s third law must be an equal and opposite reaction. The force will be greater in order to bounce off of Doug’s bat

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Minchanka [31]

Answer:

Explanation:

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3 years ago

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A combination lock has a 1.3-cm-diameter knob that is part of the dial you turn to unlock the lock. To turn that knob, you twist

galina1969 [7]

Answer:

0.04225 Nm

Explanation:

N = Force applied = 5 N

$\mu$ = Coefficient of static friction = 0.65

d = Diameter of knob = 1.3 cm

r = Radius of knob = $\frac{d}{2}=\frac{1.3}{2}=0.65\ cm$

Force is given by

$F=N\mu\\\Rightarrow F=5\times 0.65\\\Rightarrow F=3.25\ N$

When we multiply force and radius we get torque

Torque on thumb

$\tau_t=F\times r\\\Rightarrow \tau_t=3.25\times 0.0065\\\Rightarrow \tau_t=0.021125\ Nm$

Torque on forefinger

$\tau_f=F\times r\\\Rightarrow \tau_f=3.25\times 0.0065\\\Rightarrow \tau_f=0.021125\ Nm$

The total torque is given by

$\tau=\tau_t+\tau_f\\\Rightarrow \tau=0.021125+0.021125\\\Rightarrow \tau=0.04225\ Nm$

The most torque that exerted on the knob is 0.04225 Nm

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3 years ago

A 45-mH inductor is connected in series with a 60-Ω resistor through a 15-V dc power supply and a switch. If the switch is close

egoroff_w [7]

Answer:

The current is 0.248 A

Explanation:

Given that,

Inductor $L= 45\times10^{3}\ H$

Resistance $R= 60\Omega$

Voltage = 15 volt

Time $t =7.0\times10^{-3}\ sec$

We need to calculate the current

Using formula of current

$I=\dfrac{V}{R}(1-e^{\dfrac{-R}{L}}t)$

Where, V = voltage

R = resistance

L = inductance

T = time

Put the value into the formula

$I=\dfrac{15}{60}(1-e^{\dfrac{-60}{45\times10^{3}}}\times7\times10^{-3})$

$I=0.248\ A$

Hence, The current is 0.248 A.

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3 years ago

How does changing the wavelength alter the frequency of the wave? & How does altering frequency alter pitch?

Rufina [12.5K]

for a given type of wave in a given medium a larger frequency means a smaller wavelength

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Wouldn’t it be 1. resistance is high compared to the voltage and with less resistance, higher current

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