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IRINA_888 [86]
3 years ago
6

Which is not true regarding reaction rates? (2 points)

Chemistry
1 answer:
PtichkaEL [24]3 years ago
5 0

Let us consider each statement one by one

a) Catalysts are the substance which alter the reaction pathway where activation energy of reaction is less that the un catalyzed reaction. They are not used up in the reaction . the catalyst is restored in the reaction.

b) As mentioned above, the catalyst speed up reaction by lowering the activation energy

c) During a reaction the reactants are consumed up and products are formed. so there is a decrease in concentration of reactant.

Thus all the above statements are true.

D) the rate of decrease in concentration of reactants depends upon the coefficient of reactant in balanced chemical reaction.

For example

H_{2} (g)  + \frac{1}{2} O_{2} (g) -->    H_{2}O(g)

Here the rate of decrease in concentration of hydrogen will be double the rate of decrease in concentration of oxygen.

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In the induced fit model of enzymes, a substrate associates itself with which part of an enzyme?
NNADVOKAT [17]
Hello.

Active site of the enzyme.

Have a nice day
8 0
3 years ago
When a 5.00-g metal piece, A, was immersed in 38.0 mL of water, the water level rose to 50.0 mL. Similarly, when a 5.00-g metal
Mnenie [13.5K]

Answer:

A is denser than B as it's volume for the same mass is smaller.

Explanation:

Hello.

In this case, we first need to take into account that the density of each metal A and B is computed by dividing the mass over the volume of each metal which is actually computed by substracting the volume of water from the volume of the water and the solid:

V_A=50.0mL-38.0mL=12.0mL\\\\V_B=60.0mL-38.0mL=22.0mL

Next, we compute the densities as shown below:

\rho_A=\frac{m_A}{V_A}=\frac{5.00g}{12.0mL}=0.42g/mL\\  \\\rho_B=\frac{m_B}{V_B}=\frac{5.00g}{22.0mL}=0.23g/mL

In such a way, A is denser is B as it's volume for the same mass is smaller.

Best regards.

4 0
3 years ago
What controls traits in organisms? A.Cell Membrane B.Cell Wall C.Genes D.Punnett Square
BARSIC [14]

Answer:

I believe it's C (the genes)

3 0
4 years ago
Read 2 more answers
Question 2 (0 points)
bazaltina [42]

Answer:

The probability  of spinning red with the spinner or rolling an odd number with the  die is \dfrac{1}{8}

Explanation:

Given that,

Total color in spinner = 4

Let the area of four parts is equal in the spinner.

We need to calculate the probability of spinning red

Using formula of probability

P(A) = \dfrac{Number\ of\ red\ color\ outcome}{Total\ number\ of\ colors\ in\ the\ spinner}

Put the value into the formula

P(A)=\dfrac{1}{4}

We need to calculate the probability of odd number of the die

Using formula of probability

P(B) = \dfrac{Number\ of\ odd\ digits\ outcome}{Total\ number\ of\ digits\ in\ the\ die}

Put the value into the formula

P(B)=\dfrac{3}{6}

P(B)=\dfrac{1}{2}

We need to calculate the probability  of spinning red with the spinner or rolling an odd number with the  die

Using formula of probability of two events which is independent

P(A\ and\ B)=P(A)\times P(B)

Put the value into the formula

P(A\ and\ B)=\dfrac{1}{4}\times\dfrac{1}{2}

P(A\ and\ B)=\dfrac{1}{8}

Hence, The probability  of spinning red with the spinner or rolling an odd number with the  die is \dfrac{1}{8}

5 0
3 years ago
Will bromine react with sodium and why?
Archy [21]

<span><span>When you write down the electronic configuration of bromine and sodium, you get this

Na:
Br: </span></span>

<span><span />So here we the know the valence electrons for each;</span>

<span><span>Na:  (2e)
Br:  (7e, you don't count for the d orbitals)

Then, once you know this, you can deduce how many bonds each can do and you discover that bromine can do one bond since he has one electron missing in his p orbital, but that weirdly, since the s orbital of sodium is full and thus, should not make any bond.

However, it is possible for sodium to come in an excited state in wich he will have sent one of its electrons on an higher shell to have this valence configuration:</span></span>

<span><span /></span><span><span>

</span>where here now it has two lonely valence electrons, one on the s and the other on the p, so that it can do a total of two bonds.</span><span>That's why bromine and sodium can form </span>

<span>
</span>

4 0
3 years ago
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