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IRINA_888 [86]
3 years ago
6

Which is not true regarding reaction rates? (2 points)

Chemistry
1 answer:
PtichkaEL [24]3 years ago
5 0

Let us consider each statement one by one

a) Catalysts are the substance which alter the reaction pathway where activation energy of reaction is less that the un catalyzed reaction. They are not used up in the reaction . the catalyst is restored in the reaction.

b) As mentioned above, the catalyst speed up reaction by lowering the activation energy

c) During a reaction the reactants are consumed up and products are formed. so there is a decrease in concentration of reactant.

Thus all the above statements are true.

D) the rate of decrease in concentration of reactants depends upon the coefficient of reactant in balanced chemical reaction.

For example

H_{2} (g)  + \frac{1}{2} O_{2} (g) -->    H_{2}O(g)

Here the rate of decrease in concentration of hydrogen will be double the rate of decrease in concentration of oxygen.

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Consider the positions of barium (Ba), sulfur (S), silicon (Si), and calcium (Ca) on the periodic table. The atoms of which elem
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Now, you need to know the properties of the different type of elements and the tendencies on the periodic table.


The metallic elements are, those placed on the left side of the periodic table, are the ones that release an electron more easily, so they will requiere less energy to give it up when forming chemical bonds.


The higher the metallic character the less the energy need to give up an electron.


The metallic character grows as the group number decreases (goes to the left) period increases (goes downward), so among the  elements considered, Barium will require the least amount of energy to give un an electron when forming chemical bonds.
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A 25.0-mL sample of 0.150 M hydrazoic acid, HN3, is titrated with a 0.150 M NaOH solution. What is the pH after 13.3 mL of base
tamaranim1 [39]

Answer:

pH ≅ 4.80

Explanation:

Given that:

the volume of HN₃ = 25 mL = 0.025 L

Molarity of HN₃ = 0.150 M

number of moles of HN₃ = 0.025 × 0.150

number of moles of HN₃ =  0.00375  mol

Molarity of NaOH = 0.150 M

the volume of NaOH = 13.3 mL = 0.0133

number of moles of NaOH = 0.0133× 0.150

number of moles of NaOH = 0.001995 mol

The chemical equation for the reaction of this process can be written as:

HN_3 + OH- ---> N^-_{3} + H_2O

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water

thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol

Total volume used in the reaction =  0.025 +  0.0133 = 0.0383  L

Concentration of HN_3 = \dfrac{0.001755}{0.0383} = 0.0458 M

Concentration of N^{-}_3 = \dfrac{ 0.001995 }{0.0383} = 0.0521 M

GIven that :

Ka = 1.9 x 10^{-5}

Thus; it's pKa = 4.72

pH =4.72 +  log(\dfrac{ \ 0.0521}{0.0458})

pH =4.72 + log(1.1376)

pH =4.72 + 0.05598

pH =4.77598

pH ≅ 4.80

3 0
3 years ago
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