3. What will happen to the black bass and blue gill as the floor of the ponds fills with organic

If you were in charge of designing a wire to carry electricity across your city, state or province, which of

Anon25 [30]

Answer:

Thin, aluminium and buried underground.

Explanation:

When it comes to electrification of a state or province, some characteristics of the wire to use must be considered. This would help to minimize and avoid power loss and wire burns.

i. The wire to use should be thin, and a quite number can be twisted one against the other so as to increase the surface area for heat dissipation.

ii. Aluminium wire is more preferable for this project. It has a high melting point, and reduces energy loss.

iii. Burying the wire underground through an insulator is the best choice, though expensive but would preserve the wire from external influence.

7 0

2 years ago

A pitcher throws a 0.140 kg baseball, and it approaches the bat at a speed of 35.0 m/s. The bat does Wnc = 75.0 J of work on the

Eva8 [605]

Answer:

The speed of the ball is 42.5 m/s

Explanation:

The initial kinetic energy of the ball is:

$K_1=\frac{1}{2} m v_0^2=\frac{1}{2}*0.140 kg*(35.0 m/s)^2$ = 85.75 J

The speed of the ball after leaving the bat is:

$K_2=K_1+W_{nc}\\ \frac{1}{2}mV^2= 85.75 J + 75 J\\ (\frac{1}{2}mV^2)2=( 160.75 J)2\\ mV^2= 321.5 J\\ V^2= \frac{321.5 J}{0.140kg} \\ V=\sqrt{\frac{321.5 J}{0.140kg}}$

V=47.92 m/s

Using kinematic equation we can find the speed of the ball after being 25 m above the point of collision:

$V_f^2-V^2=-2gh$

$V_f^2-(47.92 m/s)^2=-2*9.81m/s^2*25m$

$V_f^2=-2*9.81m/s^2*25m+(47.92 m/s)^2$

$V_f=\sqrt{-2*9.81m/s^2*25m+(47.92 m/s)^2}$

$V_f=42.5m/s$

3 0

2 years ago

Does a wave with the high-pitched have a very low frequency

xeze [42]

No it's the opposite, ths higher the pitch the greater the frequency.

3 0

3 years ago

Suppose you drive an average of 25 miles a day, for a total of 60 years in a lifetime. The total distance you would have covered

Ahat [919]

The total distance you would have covered is equivalent to going around the earth 22 times.

<h3>Total distance traveled</h3>

The total distance traveled at a given speed and time of motion is calculated as follows;

Distance = speed x time

$Distance = \frac{25 \ miles}{day} \times \frac{365 \ days}{1 \ year} \times 60 \ years\\\\Distance = 547, 500 \ miles$

<h3>Distance round the Earth</h3>

The distance round the earth or circumference of the earth of the earth has been given as 25,000 miles

<h3>Number of times round the earth</h3>

$n = \frac{547,500}{25,000} \\\\ n = 21.9 \ times \ \approx 22 \ times$

Thus, the total distance you would have covered is equivalent to going around the earth 22 times.

Learn more about distance here: brainly.com/question/17273444

3 0

2 years ago

The solar system consists of the sun and nine planets moving in definite orbits around the sun. How do the outer planets differ

8090 [49]

I believe the answer is D) and also there are technically 8 planets because Pluto was considered a dwarf planet so they dont consider it a planet at all

4 0

3 years ago

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