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Irina18 [472]
3 years ago
15

While skateboarding at 19 km/h, Alana throws a tennis ball at 11 km/h to her friend Oliver. If Alana is the reference frame, the

speed of the tennis ball is km/h.
Physics
2 answers:
statuscvo [17]3 years ago
3 0
When Alana moving 19km/h, a stationary object will be perceived by her as moving toward her with 19km/h velocity. If the object is not stationary(velocity isn't zero), the speed will increase by the object velocity.

the relative speed of the tennis ball=
the speed of Alana + true speed of the tennis ball
19km/h+ 11km/h= 30km/h
Nastasia [14]3 years ago
3 0

the answer is 11km/h .. i just took the test.

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A heavy object falls with the acceleration as a light object during free fall. why?
alexgriva [62]

<u>A heavy object falls with the acceleration as a light object during free fall because:</u>

Heavy things have a large gravitational force and also have less acceleration. So both the effects exactly cancel and make the falling objects to have the same acceleration irrespective of mass.

Free fall is a unique motion which has only gravitational force that acts on an object. Objects that undergo free fall experience only have the influence of gravity and not any other force.

So when we apply newton's second law of gravity which is:

           \text {acceleration}=\frac{\text {Force}}{\text {mass}}

where,

F is the force

m is the mass

a is the acceleration

For example: When a 1000 kg elephant and a 1 kg rat fall from the same height,

The acceleration can be calculated as follows:

For elephant: F = 10000 N and m = 1000 kg. So,

           \text {acceleration}=\frac{10000}{1000}=10\ \mathrm{m} / \mathrm{s}^{2}

For rat :  F = 10 N and m = 1 kg

Thus, \text {acceleration}=\frac{10}{1}=1\ \mathrm{m} / \mathrm{s}^{2}

Hence, it shows that both the animals have the same acceleration irrespective of their mass.

6 0
3 years ago
6. The two ends of an iron rod are maintained at different temperatures. The amount of heat thatflows through the rod by conduct
motikmotik

Answer:

20cal/s

Explanation:

Question:

There are two questions. The first one has been answered:

From the formular, Power = Q/t = (kA∆T)/l

the amount heat depends on the duration of time interval, length of the iron rod, the thermal conductivity of iron and the temperature difference between the ends of the rod.

The amount of heat that flows through the rod by conduction during a given time interval does not depend upon the mass of the iron rod (D).

Second question:

The ends of a cylindrical steel rod are maintained at two different temperatures. The rod conducts heat from one end to the other at a rate of 10 cal/s. At what rate would a steel rod twice as long and twice the diameter conduct heat between the same two temperatures?

Solution:

Power = 10cal/s

Power = energy per unit time = Q/t

Where Q = energy

Power = (kA∆T)/l

k = thermal conductivity of iron

A = area

Area = πr^2

r = radius

Diameter = d = 2r

r = d/2

Area = (πd^2)/4

Length = l

∆T = change in temperature

10 = (kA∆T)/l

For a steel rod with length doubled and diameter doubled:

Let Length (L) = 2l

Diameter (D)= 2d

Area = π [(2d)^2]/4 = (π4d^2)/4

Area = 4(πd^2)/4

Using the formula Power = (kA∆T)/l, insert the new values for A and l

Power = [k × 4(πd^2)/4 × ∆T]/2l

Power = [4k((πd^2)/4) ∆T]/2l

Power = [(4/2)×k((πd^2)/4) ∆T]/l

Power = [2k(A) ×∆T]/l = 2(kA∆T)/l

Power of a steel that has its length doubled and diameter doubled = 2(kA∆T)/l

Recall initial Power = (kA∆T)/l = 10cal/s

And ∆T is the same

2[(kA∆T)/l] = 2 × 10

Power of a steel that has its length doubled and diameter doubled = 20cal/s

4 0
3 years ago
What happens to the current in a circuit when the resistance is increased
VikaD [51]

then the current will decrease.

hope this helps :)

5 0
3 years ago
An automobile is traveling away from Jill and towards Jack. The horn is honking, producing a sound wave.
wlad13 [49]

Answer:

a. The sound will travel at the speed to both Jill and Jack

b. Jack

Explanation:

a. Doppler effect describes how the frequency of a sound wave changes with regards to an observer that has relative motion to the sound source;

The Doppler effect is given by the following formula;

For a sound that is moving away, as observed by Jill, we have;

f' = \dfrac{(v - v_0)}{(v + v_s)} \cdot f =  \dfrac{v }{(v + v_s)} \cdot f

For approaching sound, as observed by Jack, we have;

f' = \dfrac{(v + v_0)}{(v - v_s)} \cdot f =  \dfrac{v }{(v - v_s)} \cdot f

Where;

f = The sound wave's actual frequency

f' = The frequency of the moving sound to the observer

v = The speed of the sound wave

v₀ = The observer's velocity = 0

v_s = The velocity of the source (the automobile honking) of the sound wave

From the above equation, we have that the speed of sound, 'v', is the same to both the source, and the observer although the frequency, and therefore, the wavelength of the sound alternatively increases or decreases

b. From the Doppler effect equation, the person who will hear the highest frequency is given by the formula for the frequency when the sound is approaching the observer, which has the lower denominator

Therefore, given that the automobile is travelling towards Jack, jack will hear the higher frequency

5 0
3 years ago
The surface tension of isopropanol in air has a value of 23.00 units and the
Y_Kistochka [10]

Answer:

It's A & C

Explanation:

:p

7 0
3 years ago
Read 2 more answers
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