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Marina CMI [18]
3 years ago
15

Intensity of light in SI system​

Physics
1 answer:
Rom4ik [11]3 years ago
4 0

Answer: candela

Explanation:

The SI unit for the measurement of intensity is referred to as the candela. The candela is simply used in the measurement of the visual intensity with regards to light sources such as the bulb we have in torches or the light bulbs that we have in our various homes. It is the power that a light source emits in a certain direction.

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Answer:

humans and whales are both mammals

humans and whales can breathe air

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As longitudional waves travel, particles in the medium are pushed together and then pulled apart. We call this
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Compression and rarefaction.
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The heat of fusion for water is 334 kJ/kg. How much thermal energy is required to
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is it right?
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What is the si unit of power?
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A bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in the bloc
UkoKoshka [18]

The ratio of the kinetic energy of the block/bullet system immediately after the collision to the initial kinetic energy of the bullet is 0.78 %.

<h3>Final velocity of the block/bullet system</h3>

Apply the principle of conservation of energy to determine the final velocity of the block/bullet system.

K.E = P.E

¹/₂mv² = mgh

¹/₂v² = gh

v² = 2gh

v = √2gh

where;

  • h is the maximum height reached by the system
  • v is the initial velocity of the system

v = √(2 x 9.8 x 1.1)

v = 4.64 m/s

<h3>Initial velocity of the bullet</h3>

Apply the principle of conservation of linear momentum.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

  • u₁ is the initial velocity of the bullet
  • u₂ is the initial velocity of the block
  • v is the final velocity after collision
  • m₁ is mass bullet
  • m₂ is mass of block

(0.0075)u₁ + (0.95)(0) = 4.64(0.0075 + 0.95)

0.0075u₁ = 4.4428

u₁ = 4.4428/0.0075

u₁ = 592.37 m/s

<h3>Initial kinetic energy of the bullet</h3>

K.Ei = ¹/₂m₁u₁²

K.Ei = ¹/₂(0.0075)(592.37)²

K.Ei = 1,315.88 J

<h3>Final kinetic energy of the block/bullet system</h3>

K.Ef = ¹/₂(m₁ + m₂)v²

K.Ef = ¹/₂(0.0075 + 0.95)(4.64)²

K.Ef = 10.31 J

<h3>Ratio of final kinetic energy to initial kinetic energy</h3>

= K.Ef/K.Ei x 100%

= (10.31 / 1,315.88) x 100%

= 0.78 %

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

4 0
2 years ago
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