Your answers are correct. I love the Universal formula.
The density of gasoline is 0.7 g/cm3, and the density of water is 1 g/cm3. Thus the mass of the gasoline is 55*0.7 = 38.5g and the mass of the water is 60g.
Combining the 55 cm3 and 60 cm3 of substances with the aforementioned masses yields a volume of 55+60 = 115cm3 and a mass of 38.5+60 = 98.5g. The density is therefore 98.5/115 = 0.86 g/m3.
Answer:
3°F, 0°F, -11°F, -16°F, -20°F
Explanation:
The Fahrenheit scale is a temperature scale proposed in 1724 by the physicist Daniel Fahrenheit.
In this scale:
- The freezing point of water is set at 32 degrees
- The boiling point of water is set at 212 degrees
One degree in the Fahrenheit scale is indicated with the symbol 
.
The equivalence between temperature in Celsius degrees and Fahrenheit degrees is as follows:
to convert from Fahrenheit to Celsius
to convert from Celsius to Fahrenheit
The Fahrenheit scale is an increasing monotonic scale, it means that temperature goes from negative values towards positive values without interruption. Therefore, the temperatures listed from warmest to coldest are:
3°F, 0°F, -11°F, -16°F, -20°F
Answer:
ΔSv = 0.1075 KJ/mol.K
Explanation:
Binary solution:
∴ a: solvent
∴ b: solute
in equilibrium:
- μ*(g) = μ(l) = μ* +RTLnXa....chemical potential (μ)
⇒ Ln (1 - Xb) = ΔG/RT
∴ ΔG = ΔHv - TΔSv
⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R
∴ Xb → 0:
⇒ Ln(1) = ΔHv/RT - ΔSv/R
∴ T = T*b....normal boiling point
⇒ 0 = ΔHv/RT*b - ΔSv/R
⇒ ΔSv = (R)(ΔHv/RT*b)
⇒ ΔSv = ΔHv/T*b
∴ T*b = 80°C ≅ 353 K
⇒ ΔSv = (38 KJ/mol)/(353 K)
⇒ ΔSv = 0.1075 KJ/mol.K
