Answer:
CH2- CH3
|
CH3 - CH2 - C - CH - CH2 - CH2 - CH3
| |
CH3 CH3
Explanation:
Heptane
CH3 - CH2 - CH2 - CH2 - CH2 - CH2 - CH3
3 ethyl 3, 4 dimethylheptane
CH2- CH3
|
CH3 - CH2 - C - CH - CH2 - CH2 - CH3
| |
CH3 CH3
Answer:
Because the particles are unable to overcome intermolecular attractions is the answers.
Explanation:
Answer:
so you can do the maths your self
Explanation:
isotopes are elements with he same proton number but difference in their neutron number
- proton number is also known as the atomic number
- mass number is the sum of the proton number and the neutron number
- mass number = proton number + neutron number
133.0 grams and 72.0 grams of Li2CO3 and Ca would be formed respectively.
From the equation of the reaction:
The mole ratio of Li to Li2CO3 is 2:1 while that of Li to Ca is also 2:1.
Mole of 25.0 grams of Li = mass/molar mass
= 25/6.94
= 3.6 moles
Equivalent of mole of Li2CO3 = 3.6/2
= 1.8 moles
- Amount of Li2CO3 formed = mole x molar mass
= 1.8 x 73.89
= 133 grams
Equivalent mole of Ca = 3.6/2
= 1.8 moles
- Amount of Ca formed = 1.8 x 40
= 72 grams
More on stoichiometric calculations can be found here: brainly.com/question/2563006?referrer=searchResults
Answer:
The density of O₂ gas is 1.71
Explanation:
Density is a quantity that allows you to measure the amount of mass in a given volume of a substance. So density is defined as the quotient between the mass of a body and the volume it occupies:
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P * V = n * R * T
So, you can get:
The relationship between number of moles and mass is:
Replacing:
So:
Knowing that 1 mol of O has 16 g, the molar mass of O₂ gas is 32 .
Then:
In this case you know:
- P=1.27 atm
- molar mass of O₂= 32 .
- R= 0.0821
- T= 16 °C= 289 °K (0°C= 273°K)
Replacing:
Solving:
density= 1.71
<u><em>The density of O₂ gas is 1.71 </em></u><u><em></em></u>