In your problems the possible solution is this one:
<span><span>F<span>fr</span></span>=<span>μk</span><span>FN</span>=<span>μk</span>mg</span><span>0.5(50000kg)(−9.8<span>m<span>s2</span></span>)</span><span>=−245000N</span>
<span>a=F/m</span><span>−245000N/50000kg</span><span>=−4.9<span>m<span>s2</span></span></span><span>t=<span><span>v−<span>v0</span></span>a</span></span><span><span>0−10<span>ms</span></span><span>−4.9<span>m<span>s2</span></span></span></span><span><span>=2s
I hope you understand and satisfied with my answer</span></span>
Aspartame (C₁₄H₁₈N₂O₅) is a solid used as an artificial sweetener. its combustion produces carbon dioxide gas, liquid water, and nitrogen gas
C₁₄H₁₈N₂O₅ + 16O₂-----> 14CO₂ + 9H₂O + N₂.
As it can be seen from the equation, that the coefficient of nitrogen gas in the balanced equation for the reaction is 1.
So the answer here is 1 only that is coefficient of nitrogen gas in the balanced equation for the reaction is 1.
Answer:
The sun'll likely absorb the radiation if it is close enough (Which it will never be)
Explanation:
The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is 6.18 * 10⁴ Kg of ammonia.
<h3>What mass in kilograms of ammonia are required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄?</h3>
The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is determined from the mole ratio of the reaction.
The mole ratio of the reaction is obtained from the balanced equation of the reaction given below:
- 2NH₃(g) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)
Mole ratio of NH₃ and (NH₄)₂SO₄ is 2: 1
Mass of 2 moles of ammonia = 2 * 17 = 34 g
Mass of 1 mole of (NH₄)₂SO₄ = 132 g
Mass of ammonia required = 34/132 * 2.40 × 10⁵ kg
Mass of ammonia required = 6.18 * 10⁴ Kg of ammonia.
In conclusion, the mole ratio is used to determine the mass of ammonia required.
Learn more about mole ratio at: brainly.com/question/19099163
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