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vredina [299]
3 years ago
15

Without calculation what is the approximate atomic mass of neon

Chemistry
1 answer:
Aleksandr [31]3 years ago
8 0

20 u

You can’t do this without some calculation.

The easiest way is to argue that most atoms of neon have <em>10 protons</em> and 1<em>0 neutrons</em>.

Each proton and neutron has a mass of about 1 u, so the approximate atomic mass of neon is 20 u.


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Exactly how many -OH groups are found in a 6 carbon alditol?
mr Goodwill [35]

Answer:

The number of  OH group found in found in a 6 carbon alditol is  6

Explanation:

The  structure of a 6 carbon alditol is shown on the first uploaded image

8 0
3 years ago
Se construye una pila galvánica con una barra de cobre sumergida en una disolución 1M de cationes Fe+2 y una barra de plata sume
pashok25 [27]

Answer:

El potencial celular estándar, E_{cell} is +0.46 V

Explanation:

Las reacciones de media célula son;

Media reacción del ánodo Cu²⁺ + 2e⁻ ↔ Cu, E ° = 0.34 V

Media reacción catódica 2Ag + 2e⁻ ⁻ 2Ag, E ° = 0.80 V

Sin embargo tenemos para hierro Fe²⁺ + 2e⁻ ↔ Fe, E ° -0.44 V

y Fe³⁺ + e⁻ ↔ Fe²⁺, E ° = 0.77 V

 que es más alta que la del cobre presente, por lo tanto, el cobre se oxidará en el ánodo

Por lo tanto, en el ánodo, tendremos

Cu → Cu²⁺ + 2e⁻ (E ° = -0.34 V)

En el cátodo

2Ag + 2e⁻ → 2Ag (E ° = 0.80 V)

E_{cell} = E_c + E_a = -0.34 + 0.8 = +0.46 \, V

El potencial celular estándar, E_{cell} = +0.46 V

4 0
3 years ago
What is the most common isotope for element X
ankoles [38]

Answer:

isotope 2

Explanation:

it has the highest percentage abundance

5 0
2 years ago
A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. Wha
Ainat [17]

We have that the molecular weight (3sf) of the compound (g/mol)

m=44.15g/mol

From the question we are told

A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. What is the molecular weight (3sf) of the compound (g/mol).

Generally the equation for the Rouault's law is mathematically given as

P=P_0 N

22.67=23.8*\frac{\frac{12.5}{18}}{\frac{125}{18}+\frac{15}{m}}\\\\\6.95+\frac{15}{m}=7.29\\\\\frac{15}{m}=7.29-6.95\\\\m=\frac{15}{0.34}\\\\m=44.11g/mol

Therefore

The molecular weight (3sf) of the compound (g/mol)

m=44.15g/mol

For more information on this visit

brainly.com/question/17756498

4 0
2 years ago
Need help balancing these ​
kari74 [83]
The answer would be 1,3,1,3
3 0
3 years ago
Read 2 more answers
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