The balance equation for the reaction between sodium bicarbonate and hydrochloric acid:
The reactants and react in the ratio 1:1. So we use the mass of sodium bicarbonate and molar mass to find the number of moles produced.
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Again we use the fact that the stochiometric ratio are 1:1:1:1:1, hence the moles of are 24.977moles.
So we used the ideal gas law , where P is the pressure, V is the volume, R the gas constant, is and T is the temperature in kelvins. We make V the subject
The answer is supposed to be in L, , so
The angle of incoming sunlight varies at different places.
The mass, in grams, of the chlorine gas will be 0.84 grams
<h3>Mass of gases at STP</h3>
At standard temperature and pressure, 22.4 L of gas has 1 mole of the gas in it.
This time, what we have is 265 mL of the gas at STP. 265 ml is equivalent to: 265/1000 = 0.265 L
If.
22.4 L = 1 mole
Then,
0.265 L = 0.265 x 1/22.4 = 0.01183 moles
This means that 0.01183 moles of chlorine is present in the gas at STP.
Mass of 0.01183 moles of chlorine = moles x molar mass.
The molar mass of chlorine gas is 71
Mass of the chlorine gas = 0.01183 x 71 = 0.84 grams
More on gases at STP can be found here: brainly.com/question/14004233
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It has a tetrahedral molecular geometry.
as you go deeper into the ocean temperature decreases and pressure increases to much for a body to withstand