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harina [27]
3 years ago
12

According to the law of universal gravitation, any two objects are attracted to each other. The strength of the gravitational fo

rce depends on the masses of the objects and their distance from each other.
Many stars have planets around them. If there were no gravity attracting a planet to its star, the planet's motion would carry it away from the star. However, when this motion is balanced by the gravitational attraction to the star, the planet orbits the star.

Two solar systems each have a planet the same distance from the star. The planets have the same mass, but Planet A orbits a more massive star than Planet B.


Which of the following statements is true about the planets?
A.
Planet B is more attracted to its star than Planet A.
B.
Planet B will keep orbiting its star longer than Planet A.
C.
Planet A orbits its star faster than Planet B.
D.
Planet A has a longer year than Planet B.

Physics
1 answer:
hodyreva [135]3 years ago
7 0

Answer:

C. Plant A orbits its star faster than Plant B

Explanation:

Did it on study island

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94. The diagram shows the orbit of a satellite
Valentin [98]

Answer:

7.65x10^3 m/s

Explanation:

The computation of the satellite's orbital speed is shown below:

Given that

Earth mass, M_e = 5.97 × 10^24 kg

Gravitational constant, G = 6.67 × 10^-11 N·m^2/kg

Orbital radius, r = 6.80 × 10^6m

Based on the above information

the satellite's orbital speed is

V_o = √GM_e ÷ √r

= √6.67 × 10^-11 × 5.97 × 10^24 ÷ √6.80 × 10^6

=  7.65x10^3 m/s

4 0
3 years ago
What is used to measure the speed of a moving vehicle along the road​
Romashka [77]

Answer:

Speedometer

Explanation:

Speedometer

8 0
3 years ago
Read 2 more answers
A convex thin lens with refractive index of 1.50 has a focal length of 30cm in air. When immersed in a certain transparent liqui
GalinKa [24]

Answer:

n_l = 1.97

Explanation:

given data:

refractive index of lens 1.50

focal length in air is 30 cm

focal length in water is -188 cm

Focal length of lens is given as

\frac{1}{f} =\frac{n_2 -n_1}{n_1} * \left [\frac{1}{r1} -\frac{1}{r2}   \right ]

\frac{1}{f} =\frac{n_{g} -n_{air}}{n_{air}} * \left [\frac{1}{r1} -\frac{1}{r2}   \right ]

\frac{1}{f} =\frac{n_{g} -1}{1} * \left [\frac{1}{r1} -\frac{1}{r2}   \right ]

focal length of lens in liquid is

\frac{1}{f} =\frac{n_{g} -n_{l}}{n_{l}} * \left [\frac{1}{r1} -\frac{1}{r2}   \right ]

                =\frac{n_{g} -n_{l}}{n_{l}}  [\frac{1}{(n_{g} - 1) f}

rearrange fron_l

n_l = \frac{n_g f_l}{f_l+f(n_g-1)}

n_l = \frac{1.50*(-188)}{-188 + 30(1.50 -1)}

n_l = 1.97

7 0
3 years ago
If you are over-driving your headlights and you see an object ahead, you will_____. be given the right-of-way from other vehicle
SashulF [63]

Answer: not be able to stop in time to miss the object

Explanation:

The phrase "Over-driving your headlights" means that a person is driving at such a speed that the vehicle's stopping distance is greater than the maximum viewable distance with the headlights on.

When this occurs, it will be impossible for the vehicle to stop moving in time to avoid an object viewed by the driver in the range of his headlights.

This is a <u>dangerous driving practice</u> and can be avoided by driving at <u>reduced speeds</u>.

5 0
3 years ago
Help me quickly! please!!!
stepan [7]

Answer:

(a) 6,000,000J      

(b)  3,000,000J

(c)  For A 20,000W

But for B 10,000W

6 0
3 years ago
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