a solid mass of 25 g is mixed with 60 g of a solution. a chemical reaction takes place and a gas is produced. the final mass of
2 answers:
<u>Answer:</u> The mass of gas released is 10 grams.
<u>Explanation:</u>
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
The chemical equation for the reaction of solid with solution follows:
Let the mass of gas be 'x' grams
We are given:
Mass of solid = 25 grams
Mass of solution = 60 grams
Mass of mixture = 75 grams
Total mass on reactant side = 25 + 60 = 85
Total mass on product side = 75 + x
So, by applying law of conservation of mass, we get:
Hence, the mass of gas released is 10 grams.
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When an electron in an atom absorbed a photon, the energy of the electron changed by 2.94 × 10⁻¹⁹. The frequency of the photon is 4.4 × 10¹⁴ Hertz .
<h3>How to calculate the frequency of photon ?</h3>To calculate the frequency of photon use the expression
E = hv
where,
E = Energy
h = Planck's Constant
v = frequency (Hz)
Put the value in above formula we get
E = hv
2.94 × 10⁻¹⁹ = 6.6 × 10⁻³⁴ × v
v =
= 0.44 × 10¹⁵
= 4.4 × 10¹⁴
Thus from the above conclusion we can say that When an electron in an atom absorbed a photon, the energy of the electron changed by 2.94 × 10⁻¹⁹. The frequency of the photon is 4.4 × 10¹⁴ Hertz .
Learn more about the Plank's Constant here: brainly.com/question/27163891
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Mass of Oxygen : 18.8 g
<h3>Further explanation</h3>Reaction(balanced) :
4Fe + 3O₂ → 2Fe₂O₃
mass Fe = 43.7 g
mol Fe(MW= 55,845 g/mol) :
mol O₂ : mol Fe = 3 : 4, so mol O₂ :
Mass O₂(MW=32 g/mol) :
Or simply you can Conservation of mass, where the masses before and after the reaction are the same
<em>mass reactants=mass products</em>
mass iron+mass oxygen=mass iron (III) oxide
43.7 g + mass oxygen=62.5 g
mass oxygen = 62.5 - 43.7 = 18.8 g
Answer:
0.003 M
Explanation:
The difference potential on an electrochemical cell can be calculated by the Nernst equation, which is, in its modified form:
ΔE = (-0.0592/n)*logQ
Where n is the number of electrons involved in the reaction, and Q is the coefficient of the reaction. The reaction on that is
Zn⁺²(cathode) → Zn⁺²(anode)
And 2 electrons are being replaced on this equation to the solution of ZnSO₄.
Q = [Zn⁺²(anode)]/[Zn⁺²(cathode)]
To be spontaneous, the cathode must have a higher value of reduction potential, because the reduction must happen at it, and the oxidation must happen in the anode (electrons flow from anode to cathode). Thus, [Zn⁺²(cathode)] = 0.500 M.
0.065 = (-0.059/2)*log([Zn⁺²(anode)]/0.500)
log([Zn⁺²(anode)]/0.500) = -2.2034
[Zn⁺²(anode)]/0.500 =
[Zn⁺²(anode)]/0.500 = 6.26x10⁻³
[Zn⁺²(anode)] = 0.003 M