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3 years ago

Write the empirical formula of at least four binary iconic compounds that could be formed from the following ions:

Chemistry

1 answer:

Nat2105 [25]3 years ago

7 0

Explanation:

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Help me get this right no links

Kisachek [45]

Answer:

The moons gravitational pull on Earth

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3 years ago

if two molecules of hydrochloric acid and one atom of magnesium are the reactants of a single replacement reaction how many magn

Margarita [4]

The reaction formula is 2HCl + Mg = MgCl2 + H2. There are one atom of magnesium involved and the number of atoms will not change, So the answer is one magnesium ion.

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3 years ago

Describe one way the respiratory and nervous system work together

DiKsa [7]

<h2>♨ANSWER♥</h2>

The respiratory system supplies oxygen to the blood and removes carbon dioxide. The brain monitors respiratory volume and blood gas levels. The brain regulates respiratory rate.

<u>☆</u><u>.</u><u>.</u><u>.</u><u>hope this helps</u><u>.</u><u>.</u><u>.</u><u>☆</u>

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2 years ago

How do I solve for V1 in this equation

arlik [135]

Answer:

Explanation:

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

<u>First of all cross multiply</u>

That's

$P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}$

<u>Next divide both sides by </u> $P_{1}T_{2}$ <u> in order to isolate </u> $V_{1}$

We have

$\frac{P_{1}V_{1}T_{2}}{P_{1}T_{2}} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}$

We have the final answer as

$V_{1} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}$

Hope this helps you

3 0

4 years ago

0.25 mol of nitric acid is used to make a 0.10 M nitric acid solution. How many grams of solute was used?

Yanka [14]

Answer:

15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution

Explanation:

Step 1: Data given

Nitric acid = HNO3

Molar mass of H = 1.01 g/mol

Molar mass of N = 14.0 g/mol

Molar mass O = 16.0 g/mol

Number of moles nitric acid (HNO3) = 0.25 moles

Molairty = 0.10 M

Step 2: Calculate molar mass of nitric acid

Molar mass HNO3 = Molar mass H + molar mass N + molar mass (3*O)

Molar mass HNO3 = 1.01 + 14.0 + 3*16.0

Molar mass HNO3 = 63.01 g/mol

Step 3: Calculate mass of solute use

Mass HNO3 = moles HNO3 * molar mass HNO3

Mass HNO3 = 0.25 moles * 63.01 g/mol

Mass HNO3 = 15.75 grams

15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution

7 0

3 years ago