On connecting a 9V battery to a Capacitor consisting of two circular plates of radius 0.066 m separated by an air gap of 2. 0 mm. The charge on the positive plate is 544.7 ×10⁻¹² C.
Capacitance of the capacitor is determined by the area of the plate of Capacitor and distance between the plates of capacitor.
Let the area of the Capacitor be A , radius of circular plates be r and distance between the plates of capacitor be d.
Given, Voltage, V = 9V
Radius, r = 0.066m
Distance, d = 2mm = 0.002m
Area of the Capacitor, A = πr²
A = π(0.066)²
A = 0.013m²
Capacitance, C = ε₀A / d
C = 8.85×10⁻¹²×0.013/0.002
C = 60.5 ×10⁻¹² F
C = 60.5 pF
We know that Q = CV where Q is the charge on capacitor.
Q = 60.5 ×10⁻¹² × 9
Q= 544.7 ×10⁻¹² C
Since, both plates of a capacitor acquire equal and opposite charge.
Hence the charge on the positive plate of the capacitor is 544.7 ×10⁻¹² C.
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The answer is option C) The car experienced negative acceleration with velocity in the positive direction.
Answer & Explanation:
A girl is driving a bicycle at a velocity of 30m/s at 40 degree North west.
Considering the above sentence, the magnitude of the bicycle velocity is 30 meters per second and the direction of the motion of the bicycle is 40 degree North west. So, the bicycle is having both magnitude and direction, so the velocity is a vector quantity.
Answer:
Explanation:
Given
velocity of boat with respect to river
velocity of river is
River is 3.5 km wide
Suppose boat leaves at an angle of with vertical such that it reaches exactly opposite end of initial Point
Therefore
component will balance the river Flowso that sin component helps to cross the river
<span>1080 degrees buddy bye</span>