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natta225 [31]
3 years ago
6

A model is considered to scale if its relative proportions are equal to that of the object its modeling. If a building is twice

as tall as it is wide, then a scale model of the building will also be twice as tall as it is wide regardless of how big the model is relative to the real building.
The picture below is of a relief globe. The height of objects (above or below sea level) on a relief globe use a different scale than their widths and lengths.

Without knowing the scale used for the heights of objects, what could be figured out accurately using this relief globe?

A. Where the highest and lowest places on earth are
B. The kinds of terrain on different parts of the earth
C. How high above sea level a certain mountain is
D. How much later the sun sets on top of a mountain than in a valley

Physics
1 answer:
zhenek [66]3 years ago
3 0

Answer:

The correct option is B.

B. The kinds of terrains on different paths of the earth.

Explanation:

Looking at relief globe, we can clearly see the heights and types different areas of the world. We can not accurately determine the height of any area because we do not know the scale factor. We certainly cannot determine the highest or lowest point on the earth because it is impossible to calculate just from looking at the globs. We cannot find the height of a mountain above sea level or any other height measurement. It is also no where related to time of sun rising and setting in a particular area.

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Suppose that you are swimming in a river while a friend watches from the shore. In calm water, you swim at a speed of 1.25 m/s .
aliya0001 [1]

Answer: The observing friend will the swimmer moving at a speed of 0.25 m/s.

Explanation:

  • Let <em>S</em> be the speed of the swimmer, given as 1.25 m/s
  • Let S_{0} be the speed of the river's current given as 1.00 m/s.

  • Note that this speed is the magnitude of the velocity which is a vector quantity.
  • The direction of the swimmer is upstream.

Hence the resultant velocity is given as, S_{R} = S — S 0S_{0}

S_{R} = 1.25 — 1

S_{R} = 0.25 m/s.

Therefore, the observing friend will see the swimmer moving at a speed of 0.25 m/s due to resistance produced by the current of the river.

6 0
3 years ago
#2
sladkih [1.3K]

Answer:

mass and distance

Explanation:

force is mass while motion can also be regard as distance or movement

3 0
3 years ago
A diffraction grating with 1000 lines per mm is used in a spectrometer to measure the wavelengths of light emitted from a gas di
frez [133]

Answer:

= 9.8°

Explanation:

Width of one slit (a₁ ) = 1 / 1000 mm=0.001 mm = 10⁻⁶ m.

width of one slit in case 2 (a₂ ) = 1/500 =2 x 10⁻⁶ m

angular position of fringe, Sinθ  = n λ /a

n is order of fringe , λ is wave length of light and a  is slit aperture

So Sinθ  ∝ 1 / a

Sin θ₁ /Sin θ₂ = a₂/a₁ ;

Sin20°/sinθ₂ = 2 / 1

sinθ₂ = Sin 20° / 2 = .342/2 = .171

θ₂ = 9.8 °

4 0
3 years ago
.125 kg piece of rubber slows down from 20 m/s to 10m/s as it slides along ice for 102 meters calculate the force of friction
Paha777 [63]

Answer:

-0.18 N

Explanation:

The motion of the piece of rubber is a uniformly accelerated motion, so we can find its acceleration using the suvat equation:

v^2-u^2=2as

where:

v = 10 m/s is the final speed

u = 20 m/s is the initial speed

a is the acceleration

s = 102 m is the distance  covered

Solving for a,

a=\frac{v^2-u^2}{2s}=\frac{10^2-20^2}{2(102)}=-1.47 m/s^2

The net force acting on the piece of rubber is the force of friction; according to Newton's second law of motion, the force is equal to the product of mass (m) and acceleration (a):

F=ma

Here we have

m = 0.125 kg is the mass

Therefore, the force of friction is:

F=ma=(0.125)(-1.47)=-0.18 N

And the negative sign means the direction of the force is opposite to the direction of motion.

5 0
3 years ago
1) The _________ would be considered a mid-range club? (hint: golf clubs)
sergey [27]
C. course conditions
If the grass is grown then the golf ball will not be able to able to cover good ground distance
7 0
3 years ago
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