Answer:
The maximum height it reaches will be 20 m.
The time taken by it to reach the height will be: t = 2 seconds.
Explanation:
We know the equation of the motion under gravity
v² - u² = 2gs
u = initial velocity = 20 m/s
v = final velocity = 0 m/s
so
substituting u = 20 m/s, v = 0 m/s, g = -10 and
m
Therefore, the maximum height it reaches will be 20 m.
We know the equation
u = gt
substitute u = 20, g = 10
20 = 10 × t
t = 20/10
t = 2 seconds
Therefore, the time taken by it to reach the height will be: t = 2 seconds.
It means that electric charge exists in integral multiples of an elementary unit of charge rather taking on continuous values.
Since Millikan was the first to measure the value of the electronic charge in his famous "oil drop" experiment, he may be the one given credit for discovering quantization of charge.
The correct formula for
this simple harmonic motion is:
x = (6.0) cos [ (3 pi) t +
pi/3 ]
A. Calculating for displacement
x at t = 2:
x =6.0 cos (19/3 pi)
x = 6 (0.5)
x = 3 m
<span>B. Velocity is equivalent
to the 1st derivative of the equation. v = dx / dt </span>
<span> Velocity v = dx/dt = -18 pi sin (3pi t + pi/3) </span>
v = - 18 pi sin (6pi +
pi/3)
v = 49.0 m/s
<span>C. Acceleration is the 2nd
derivative or the 1st derivative of velocity dv / dt</span>
Acceleration a = dv/dt = -54 pi^2 cos(3pi t + pi/3)
a = -54 pi^2 cos(3pi * 2 +
pi/3)
a = 386.34 m/s^2
D. Phase = pi/3
E. frequency f= 3pi/2pi =
1.5Hz
<span>F. period = 1/f = 1/1.5 = .6667sec </span>
Answer:
A:
Explanation:
Plane mirrors always form virtual images meaning although the object appears to be in the other side of the mirror the light rays actually originate in front of it. The image is inverted meaning that when you lift your right hand it shows your left hand rising. and with true orientation.
Answer:
The total displacement from the starting point is 1.5 m.
Explanation:
You need to sum and substract, depending on the movement (to the right, sum; to the left, substract).
First, it moves 4.3 m right and return 1.1 m. So the new distance from the starting point is 3.2 m.
Second, it moves 6.3 m right, so the new distance is 9.5 m.
Finally it moves 8 m to the left, so 9.5 m - 8 m= 1.5 m.
Summarizing, at the end the squirrel is 1.5 m from its starting point.
