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2 years ago

If two objects at different temperatures are in contact with each other, what happens to their temperatures?

1 answer:

6 0

In that case, heat energy flows from the warmer object to the cooler one.
As heat flows from one to the other, the temperature of the warmer object
falls, and the temperature of the cooler object rises. When the temperatures
are equal, the flow of heat energy from one to the other stops.

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A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material

Llana [10]

Answer:

a) $C = 40.138\,pF$ , b) $q = 16.056\,nC$ , c) $U = 3.212\,\mu J$

Explanation:

a) The capacitance of two parallel plates capacitor with dielectric is given by the following expression:

$C = K\cdot \epsilon_{o}\cdot \frac{A}{d}$

Where:

$K$ - Dielectric constant.

$\epsilon_{o}$ - Vaccum permitivity.

$A$ - Plate area.

$d$ - Distance between plates.

Hence, the capacitance of the system is:

$C = (4.00)\cdot (8.854\times 10^{-12}\,\frac{F}{m} )\cdot \left(\frac{17\times 10^{-4}\,m^{2}}{0.150\times 10^{-2}\,m}\right)$

$C = 4.014\cdot 10^{-11}\,F$

$C = 40.138\,pF$

b) The charge can be found by using the definition of capacitance:

$q = C\cdot V_{batt}$

$q = (4.014\times 10^{-11}\,F)\cdot (400\,V)$

$q = 1.606\times 10^{-8}\,C$

$q = 16.056\,nC$

c) The energy stored in the charged capacitor is:

$U=\frac{1}{2}\cdot Q\cdot V_{batt}$

$U=\frac{1}{2}\cdot (1.606\times 10^{-8}\,C)\cdot (400\,V)$

$U = 3.212\times 10^{-6}\,J$

$U = 3.212\,\mu J$

3 0

2 years ago

Read 2 more answers

You and a friend work in buildings five equal-length blocks apart, and you plan to meet for lunch. Your friend strolls leisurely

Pavel [41]

Answer:

Your friend is 2.143 blocks from the restaurant.

You are 2.857 blocks from the restaurant.

Explanation:

Let t be the time both you and your friend take to walk to the restaurant.

The distance (m) from your building to the restaurant is your walking time t times your speed v1

$s_1 = v_1t = 1.6t$

Similarly the distance (m) from your friend building to the restaurant:

$s_2 = v_2t = 1.2t$

Let b be the length (in m) of a block, the total distance of 5 blocks is 5b

$s_1 + s_2 = 5b$

$1.6t + 1.2t = 5b$

$2.8t = 5b$

$t = 5b/2.8 = 25b/14$

$s_2 = 1.2t = 1.2(25b/14) = 2.143b$

So your friend are 2.143b meters from the restaurant, since each block is b meters long, 2.143b meters would equals to 2.143b/b = 2.143 blocks. And you are 5 - 2.143 = 2.857 blocks from the restaurant.

7 0

2 years ago

Make the following conversion. 275 mm = _____ cm

scZoUnD [109]

10mm=1cm So.......... 275 mm=27.5 cm

6 0

2 years ago

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what is the acceleration of a car that slows down from 60m/s to 40 m/s during a period of 10 seconds?

algol [13]

The acceleration of the car is stated as -2 m/s², while the deceleration of the car is termed as 2 m/s².

Answer:

Explanation:

Acceleration exerted by any object in order of decrease in the speed is termed as deceleration. In other words , negative acceleration or acceleration acting in opposite direction to stop the motion of any object is termed as deceleration. The magnitude of acceleration and deceleration is same only the direction is completely opposite to each other. So the negative sign will be obtained for acceleration value of any object whose velocity slows down from initial velocity.

Here , the initial velocity was 60 m/s and the final velocity is slowed down to 40 m/s in time 10 s.

So acceleration = (Final velocity - Initial velocty)/Time

Acceleration = (40-60)/10 = -20/10 = -2 m/s².

Thus, the acceleration of the car is stated as -2 m/s², while the deceleration of the car is termed as 2 m/s².

5 0

3 years ago

What is it called after data is collected they are often arranged in a what?

valentinak56 [21]

They are often arranged in a category

3 0

2 years ago

Read 2 more answers