All categories

3 years ago

When we see a meteor shower, it means that ________.

Physics

1 answer:

Irina18 [472]3 years ago

6 0

Answer:

option A

Explanation:

The meteor shower is the celestial activity in which meteors are observed to radiate or originate from one point.

Meteors are nothing but dust or ice from the trails of comets. Most of the meteors are less than the size of the sand particle.

We will see comet shower when we earth will cross the orbit of the comet.

Hence, the correct answer is option A

You might be interested in

Action-reaction forces : Select one:

ladessa [460]

i think its B)... im not sure so dont take it seriously

4 0

3 years ago

Will give brainliest

user100 [1]

Answer:

I believe the answer is 2.5 N.......

7 0

3 years ago

The law of conservation of matter states that during a chemical reaction, the amount of matter

mixas84 [53]

Answer:

The law of conservation of matter says that in chemical reactions, the total mass of the products must equal the total mass of the reactants.

7 0

2 years ago

The parallel axis theorem relates Icm, the moment of inertia of an object about an axis passing through its center of mass, to I

erma4kov [3.2K]

Answer:

Part a)

$I_{end} = \frac{mL^2}{3}$

Part b)

$I_{edge} = \frac{2ma^2}{3}$

Explanation:

As we know that by parallel axis theorem we will have

$I_p = I_{cm} + Md^2$

Part a)

here we know that for a stick the moment of inertia for an axis passing through its COM is given as

$I = \frac{mL^2}{12}$

now if we need to find the inertia from its end then we will have

$I_{end} = I_{cm} + Md^2$

$I_{end} = \frac{mL^2}{12} + m(\frac{L}{2})^2$

$I_{end} = \frac{mL^2}{3}$

Part b)

here we know that for a cube the moment of inertia for an axis passing through its COM is given as

$I = \frac{ma^2}{6}$

now if we need to find the inertia about an axis passing through its edge

$I_{edge} = I_{cm} + Md^2$

$I_{edge} = \frac{ma^2}{6} + m(\frac{a}{\sqrt2})^2$

$I_{edge} = \frac{2ma^2}{3}$

7 0

3 years ago

A 20-kg cart travels at 20 m/s in a circle with a radius of 20 m. What is the centripetal force?

Vlad1618 [11]

Centripetal force = (mass) x (speed)² / (radius)

   = (20 kg) x (20 m/s)² / (20 m)

   = (20 x 20 / 20) (kg-meter/sec²)

   = 20 newtons

5 0

3 years ago

Read 2 more answers