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yan [13]
3 years ago
8

When dipentyl ether is treated with HI, what type of reaction occurs? both SN1 and SN2 SN2 E1 SN1 E2

Chemistry
1 answer:
masha68 [24]3 years ago
7 0

Answer:

SN2

Explanation:

The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.

The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.

Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.

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Answer:

pH = 10.9

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to say that the undergoing reaction between this buffer and OH⁻ promotes the formation of more CO₃²⁻ because it acts as the base, we can do the following:

n_{CO_3^{2-}}=0.34mol/L*0.250L+0.0585mol=0.1435mol\\\\n_{HCO_3^{-}}=0.34mol/L*0.250L-0.0585mol=0.0265mol

The resulting concentrations are:

[CO_3^{2-}]=\frac{0.1435mol}{0.25L}=0.574M \\

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Thus, since the pKa of this buffer system is 10.2, the change in the pH would be:

pH=10.2+log(\frac{0.574M}{0.106M} )\\\\pH=10.9

Which makes sense since basic OH⁻ ions were added.

Regards!

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Answer:

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