Answer:If each side of the equation has the same number of atoms of a given element, that element is balanced. If all elements are balanced, the equation is balanced. - online resource
Explanation: if not im sorry
NaOH reacts with CH3COOH in 1:1 molar ratio to produce CH3COONa
NaOH + CH3COOH → CH3COONa + H2O
Mol CH3COOH in 52.0mL of 0.35M solution = 52.0/1000*0.35 = 0.0182 mol CH3COOH
Mol NaOH in 19.0mL of 0.40M solution = 19.0/1000*0.40 = 0.0076 mol NaOH
These will react to produce 0.0076 mol CH3COONa and there will be 0.0182 - 0.0076 = 0.0106 mol CH3COOH remaining in solution unreacted . Total volume of solution = 52.0+19.0 = 71mL or 0.071L
Molarity of CH3COOH = 0.0106/0.071 = 0.1493M
CH3COONa = 0.0076 / 0.071 = 0.1070M
pKa acetic acid = - log Ka = -log 1.8*10^-5 = 4.74.
pH using Henderson - Hasselbalch equation:
pH = pKa + log ([salt]/[acid])
pH = 4.74 + log ( 0.1070/0.1493)
pH = 4.74 + log 0.717
pH = 4.74 + (-0.14)
pH = 4.60.
Answer:
- Option d. i<u><em>t is higher than the energy of both reactants and products</em></u>
Explanation:
<em>Activated complex</em>, also known as transition state, is the intermediate structure formed in the course of a chemical reaction.
The activated complex is very unstable and of short life: it is at the peak of the potential chemical diagram, and can transform either into the reactants (backward) or the products (forward).
The activation energy of the reaction is the energy needed to reach the activated complex, then both reactants and products are lower in potential chemical energy than the activated complex, which is what explains why the activated complex can transform into one or another, reactants or products.
Answer:
Explanation:
Are there any awnser choices?
Answer:
![\boxed{\sf D. \ [Ar] \ 3d5 \ 4s2}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20D.%20%5C%20%20%5BAr%5D%20%5C%203d5%20%5C%204s2%7D)
Explanation:
Manganese is a group 7 transition metal with an electronic configuration of [Ar] 3d5 4s2.
