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Burka [1]
3 years ago
10

William wanted to create a report on a geographical location with the greatest species diversity. Which ecosystem can consider f

or his report?
Physics
1 answer:
FrozenT [24]3 years ago
8 0

Answer:

The ecosystem that he should consider is the tropical rain forest ecosystem.

Explanation:

In that area, there are uncountable amounts of various plants and animals that have not all yet been discovered and who all live together to build the biome. This biome is indeed the most diverse one even at this point without the knowledge of all possible life forms.

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What is the definition of permitted orbits ?
givi [52]
.The path of a celestial body or an artificial satellite as it revolves around another body due to their mutual gravitational <span>attraction.</span>
7 0
3 years ago
What three sprites are needed to create the Space Invaders game that was discussed in the unit? spaceship, laser, enemy gnome, a
Lilit [14]

Answer: anlien, enemy gnome, spaceship

Explanation:

3 0
2 years ago
Rotational dynamics about a fixed axis: A person pushes on a small doorknob with a force of 5.00 N perpendicular to the surface
FrozenT [24]

Answer:

I = 2 kgm^2

Explanation:

In order to calculate the moment of inertia of the door, about the hinges, you use the following formula:

\tau=I\alpha     (1)

I: moment of inertia of the door

α: angular acceleration of the door = 2.00 rad/s^2

τ: torque exerted on the door

You can calculate the torque by using the information about the Force exerted on the door, and the distance to the hinges. You use the following formula:

\tau=Fd        (2)

F: force = 5.00 N

d: distance to the hinges = 0.800 m

You replace the equation (2) into the equation (1), and you solve for α:

Fd=I\alpha\\\\I=\frac{Fd}{\alpha}

Finally, you replace the values of all parameters in the previous equation for I:

I=\frac{(5.00N)(0.800m)}{2.00rad/s^2}=2kgm^2

The moment of inertia of the door around the hinges is 2 kgm^2

3 0
3 years ago
Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin
Alex777 [14]

Answer:

0.92 μC

Explanation:

In a parallel-plate capacitor, the electric field formed is equal to the charge density divited by the vacuum permisivity e0, as there are no dielectric between the plates. e0 is equal to 8.85*10^-12 C^2/Nm^2. The charge density is the total charge of each individual plate divided by its area. Then, the maximum charge allowed will be equal to:

E = \frac{o}{e_0} = \frac{Q}{Ae_0} \\ Q = E*A*e_0 = 3*10^6 N/C * (0.25*\pi *(0.21m)^2)*8.85*10^{-12}C^2/Nm^2 = 9.196 *10^{-7} C

or 0.92 μC

7 0
2 years ago
Which statement is true for a sound wave entering an area of warmer air?
Sergio [31]
The answer is A........The sound is transferred by collisions of molecules. Therefore sound waves will travel faster on warm air because collisions of molecules of air in warm air are greater.
3 0
3 years ago
Read 2 more answers
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