Answer:
a) Average Speed = 190yards/26.6s = 7.14 yards/s
b) Average Velocity = 10/26.6 = 0.38 yard/s
Complete Question;
A football player runs from his own goal line to the opposing team's goal line, returning to his ten-yard line, all in 26.6 s. Calculate his average speed and the magnitude of his average velocity. (Assume a 100 yard football field; note that the player's X-yard line is X yards from his own goal line. Enter your answers in yards/s.)
Explanation:
a) Speed = distance/time
time t = 26.6s
distance;
d1 = 100 yards (own goal line to the opposing team's goal line)
d2 = 90 yards (returning to his ten-yard line)
d = d1 + d2
d = 100 + 90 = 190 yards
Speed = 190yards/26.6s = 7.14 yards/s
b) velocity = displacement/time
time = 26.6s
displacement = 100-90 yards = 10yards
Velocity = 10/26.6 = 0.38 yard/s
