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natka813 [3]
3 years ago
5

A football player runs from his own goal line to the opposing team's goal line, returning to his ten-yard line, all in 26.6 s. C

alculate his average speed and the magnitude of his average velocity. (Enter your answers in yards/s.) HINT
Physics
1 answer:
Advocard [28]3 years ago
8 0

Answer:

a) Average Speed = 190yards/26.6s = 7.14 yards/s

b) Average Velocity = 10/26.6 = 0.38 yard/s

Complete Question;

A football player runs from his own goal line to the opposing team's goal line, returning to his ten-yard line, all in 26.6 s. Calculate his average speed and the magnitude of his average velocity. (Assume a 100 yard football field; note that the player's X-yard line is X yards from his own goal line. Enter your answers in yards/s.)

Explanation:

a) Speed = distance/time

time t = 26.6s

distance;

d1 = 100 yards (own goal line to the opposing team's goal line)

d2 = 90 yards (returning to his ten-yard line)

d = d1 + d2

d = 100 + 90 = 190 yards

Speed = 190yards/26.6s = 7.14 yards/s

b) velocity = displacement/time

time = 26.6s

displacement = 100-90 yards = 10yards

Velocity = 10/26.6 = 0.38 yard/s

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v= 4.0 m/s

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       a =\frac{F_{net} }{m} =\frac{100 N}{95 kg} =  1.05 m/s2

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