The equation of GPE is mgH, where m is mass, g is gravitational acceleration, and H is the height.
If we're solving for the change in GPE, then:
∆
= mg∆H
<u>Input our given values for m and g:</u>
∆ = 0.25 * 9.80 * ∆H
<u>The book falls from 2 meters high to 0.5 meters high, so:</u>
∆ = 0.25 * 9.80 * (2.0 - 0.5)
∆ = 0.25 * 9.80 * 1.5
∆ = 3.675 (J)
<u>Adjust for significant figures:</u>
∆ = 3.7 (J)
The change in gravitational potential energy was 3.7 (J)
If you have any questions on anything I did to get to the answer, just ask!
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Answer:
The minimum speed = 
Explanation:
The minimum speed that the rocket must have for it to escape into space is called its escape velocity. If the speed is not attained, the gravitational pull of the planet would pull down the rocket back to its surface. Thus the launch would not be successful.
The minimum speed can be determined by;
Escape velocity =
where: G is the universal gravitational constant, M is the mass of the planet X, and R is its radius.
If the appropriate values of the variables are substituted into the expression, the value of the minimum speed required can be determined.
Answer:If the kinetic and potential energy in a system are equal, then the potential energy increases. ... Stored energy decreases. Energy of motion decreases. Total energy decreases
Explanation:
Answer: 0.2 hours
Explanation: In order to solve this question we have to considerer that a recargeable battery can supply 1800 mA in one hour then we have to determine how long could this battery drive current through a long, thin wire of resistance 34 Ω .
Besides, this battery has a voltage of 12 V
so by using the Ohm law we also know that V=R*I,
Fron this we can obtain:
I= V/R= 12 V/ 34 Ω=0.35 A= 350 mA
then considering that this battery can supply 1800 mA in one hour we have this battery can supply 350 mA in x time in the form:
1hour------- 1800 mA
x hour--------350 mA
time= 350/1800= 0.2 hour
Answer:
the acceleration of object is 3m/1s
