Answer:
Im not sure if im right but this is what i got( i have no clue how to explain im sorry)
1. False
2. False
3. True
4. False
Answer:
The velocity of the center of mass of the two-ball system is 13.1 m/s.
Explanation:
Given;
mass of the first ball, m₁ = 0.5 kg
mass of the second ball, m₂ = 0.25 kg
initial velocity of the second ball, u₂ = 19.6 m/s
At the highest point the velocity of the second ball, v₂ = 0
The highest point reached by the second ball is calculated as;
v₂² = u₂² - 2gh
0 = u₂² - 2gh
2gh = u₂²
h = u₂² / 2g
h = (19.6²) / (2 x 9.8)
h = 19.6 m
The final velocity of the first ball when it had traveled 19.6 m down;
v₁² = u₁² + 2gh
v₁² = 0 + 2gh
v₁ = √2gh
v₁ = √(2 x 9.8 x 19.6)
v₁ = 19.6 m/s
The velocity of the center of mass of the two-ball system is calculated as;
![v = \frac{m_1v_1 \ + \ m_2v_2}{m_1 \ + \ m_2} \\\\v = \frac{0.5\times 19.6 \ + \ 0.25\times 0}{0.5 \ + \ 0.25} \\\\v = 13.1 \ m/s](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bm_1v_1%20%5C%20%2B%20%5C%20m_2v_2%7D%7Bm_1%20%5C%20%2B%20%5C%20m_2%7D%20%5C%5C%5C%5Cv%20%3D%20%5Cfrac%7B0.5%5Ctimes%2019.6%20%5C%20%2B%20%5C%200.25%5Ctimes%200%7D%7B0.5%20%5C%20%2B%20%5C%200.25%7D%20%5C%5C%5C%5Cv%20%3D%2013.1%20%5C%20m%2Fs)
Answer:
yes it is because 2 is close to 0 than 10.
for this we apply, Heisenberg's uncertainty principle.
it states that physical variables like position and momentum, can never simultaneously know both variables at the same moment.
the formula is,
Δp * Δx = h/4π
m(e).Δv * Δx = h/4π
by rearranging,
Δx = h / 4π * m(e).Δv
Δx = (6.63*10^-34) / 4 * 3.142 * 9.11*10^-31 * 5.10*10^-2
Δx = 6.63*10^-34 / 583.9 X 10 ⁻³¹
Δx = 0.011 X 10⁻³
for the bullet
Δx = (6.63*10^-34) / 4 * 3.142 * 0.032*10^-31 * 5.10*10^-2
Δx = 6.63*10^-34 /2.05
Δx =3.23 X 10⁻³² m
therefore, we can say that the lower limits are 0.011 X 10⁻³ m for the electron and 3.23 X 10⁻³² m for the bullet
To know more about bullet problem,
brainly.com/question/21150302
#SPJ4
Answer:
Mohammed has less kinetic energy than Autumn
Explanation:
The kinetic energy of each student is given by:
![K=\frac{1}{2}mv^2](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
where
m is the mass of the student
v is the speed of the student
Let's use the formula above to calculate the kinetic energy of each student:
- Autumn: ![K=\frac{1}{2}(50 kg)(4 m/s)^2=400 J](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7D%2850%20kg%29%284%20m%2Fs%29%5E2%3D400%20J)
- Mohammed: ![K=\frac{1}{2}(57 kg)(3 m/s)^2=256.5 J](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7D%2857%20kg%29%283%20m%2Fs%29%5E2%3D256.5%20J)
- Lexy: ![K=\frac{1}{2}(53 kg)(3 m/s)^2=238.5 J](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7D%2853%20kg%29%283%20m%2Fs%29%5E2%3D238.5%20J)
- Chiang: ![K=\frac{1}{2}(64 kg)(5 m/s)^2=800 J](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7D%2864%20kg%29%285%20m%2Fs%29%5E2%3D800%20J)
Therefore, by looking at the numbers, we see that the correct answer is
Mohammed has less kinetic energy than Autumn