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Ivan
3 years ago
10

A runner moving at a speed of 8.8m/s rounds a bend with a radius of 25m. what is the centripetal acceleration of the runner

Physics
1 answer:
nikitadnepr [17]3 years ago
8 0
Radial acceleration is = v^2/r
Therefore (8.8m/s)^2/(25m)= 3.10m/s^2

Hope this helps you! Any questions please just ask! Thank you!
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What is the difference in KE between a 52.5 kg person running 3.50 m/s and a 0.0200 kg bullet flying 450 m/s?
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Explanation:

In order to solve this problem, we must remember that kinetic energy can be calculated by means of the following equation.

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<u>For the person running</u>

<u />E_{k} =\frac{1}{2}*52.2*(3.5)^{2} \\ E_{k} =319.72[J]<u />

<u />

<u>For the bullet</u>

<u />E_{k} =\frac{1}{2} *m*v^{2}<u />

<u />E_{k} =\frac{1}{2} *0.02*(450)^{2} \\E_{k}=2025 [J]<u />

<u />

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Ek = 2025 - 319.72

Ek = 1705.28 [J]

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