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Ivan
2 years ago
10

A runner moving at a speed of 8.8m/s rounds a bend with a radius of 25m. what is the centripetal acceleration of the runner

Physics
1 answer:
nikitadnepr [17]2 years ago
8 0
Radial acceleration is = v^2/r
Therefore (8.8m/s)^2/(25m)= 3.10m/s^2

Hope this helps you! Any questions please just ask! Thank you!
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How do you think the switch controls the flow of current to the light?
nadezda [96]

Answer:

A switch interrupts the flow of current in a circuit.

Explanation:

3 0
2 years ago
For a molecule of O2 at room temperature (300 K), calculate the average angular velocity for rotations about the x or y axes. Th
Ksivusya [100]

Answer: 6.65 rad/s

Explanation:

Firstly, we need to know that according the kinetic theory of gases, the average kinetic energy KE of a molecule with i degrees of freedom is:

KE=\frac{i}{2}kT (1)

Where:

i=5 because oxigen is a diatomic molecule and has 5 degrees of freedom

k=1.38064852 (10)^{-23} \frac{m^{2}kg}{s^{2}K} is the Boltzman constant

T=300 K is the temperature

Then:

KE=\frac{5}{2}(1.38064852 (10)^{-23} \frac{m^{2}kg}{s^{2}K})(300 K) (2)

KE=1.035 (10)^{-20} \frac{m^{2}kg}{s^{2}} (3) With this value of average kinetic energy we can find the average angular velocity, with the following equation:

KE=\frac{1}{2}I \omega^{2} (4)

Where:

I is the moment of inertia

\omega is the angular velocity

Now, I=m R^{2} (5)

Being m=31.98 g/mol=0.03198 kg/mol the molar mass of Oxigen molecule and R=0.121(10)^{-9}m the distance between atoms

I=(0.03198 kg/mol)(0.121(10)^{-9}m)^{2} (6)

I=4.682(10)^{-22} \frac{kg}{mol} m^{2} (7)

Substituting (7) and (3) in (4):

1.035 (10)^{-20} \frac{m^{2}kg}{s^{2}}=\frac{1}{2} (4.682(10)^{-22} \frac{kg}{mol} m^{2}) \omega^{2} (8)

Finding \omega:

\omega=6.65 rad/s (9) This is the average angular velocity for a molecule of O2

7 0
3 years ago
A baseball goes from zero to 34 m/s in 0.188 s. What is its average acceleration? Answer in units of m/s^2
Kaylis [27]

Answer:

a_{avg} = 180.85 m/s^{2}

Given:

Initial velocity, u = 0 m/s

Final velocity, v = 34 m/s

Time interval, \Delta t = 0.188 s

Solution:

Acceleration is the rate at which the velocity of an object changes.

Thus

Average acceleration, a_{avg} = \frac{\Delta v}{\Delta t}

a_{avg} = \frac{v - u}{t - 0} = \frac{34 - 0}{0.188} = 180.85 m/s^{2}

6 0
2 years ago
What is the charge on a hypothetical ion with 35 protons and 33 electrons?
kenny6666 [7]

+2 electron charges = 2x1.6x10^-19Coulombs

7 0
2 years ago
If the temperature is held constant during this process and the final pressure is 683 torrtorr , what is the volume of the bulb
Anna [14]

Answer:

Explanation:

Let the volume of the unknown bulb = X L

The volume of the system , after opening valve = (X + 0.72 L )

Use Boyles law gas equation,

P1V1 = P2V2 ( at temperature is constant )

Given:

P1 = 1.2 atm

P2 = 683 torr

Converting mmHg to atm,

1 atm = 760 mmHg(torr)

683 mmHg = 683/760

= 0.8987 atm

1.2X = 0.8987*(X + 0.720)

1.2X = 0.8987X + 0.6471

0.3013X = 0.6471

X = 2.15 L

5 0
3 years ago
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