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2 years ago

10

A runner moving at a speed of 8.8m/s rounds a bend with a radius of 25m. what is the centripetal acceleration of the runner

1 answer:

nikitadnepr [17]2 years ago

8 0

Radial acceleration is = v^2/r
Therefore (8.8m/s)^2/(25m)= 3.10m/s^2

Hope this helps you! Any questions please just ask! Thank you!

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How do you think the switch controls the flow of current to the light?

nadezda [96]

Answer:

A switch interrupts the flow of current in a circuit.

Explanation:

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2 years ago

For a molecule of O2 at room temperature (300 K), calculate the average angular velocity for rotations about the x or y axes. Th

Ksivusya [100]

Answer: 6.65 rad/s

Explanation:

Firstly, we need to know that according the kinetic theory of gases, the average kinetic energy $KE$ of a molecule with $i$ degrees of freedom is:

$KE=\frac{i}{2}kT$ (1)

Where:

$i=5$ because oxigen is a diatomic molecule and has 5 degrees of freedom

$k=1.38064852 (10)^{-23} \frac{m^{2}kg}{s^{2}K}$ is the Boltzman constant

$T=300 K$ is the temperature

Then:

$KE=\frac{5}{2}(1.38064852 (10)^{-23} \frac{m^{2}kg}{s^{2}K})(300 K)$ (2)

$KE=1.035 (10)^{-20} \frac{m^{2}kg}{s^{2}}$ (3) With this value of average kinetic energy we can find the average angular velocity, with the following equation:

$KE=\frac{1}{2}I \omega^{2}$ (4)

Where:

$I$ is the moment of inertia

$\omega$ is the angular velocity

Now, $I=m R^{2}$ (5)

Being $m=31.98 g/mol=0.03198 kg/mol$ the molar mass of Oxigen molecule and $R=0.121(10)^{-9}m$ the distance between atoms

$I=(0.03198 kg/mol)(0.121(10)^{-9}m)^{2}$ (6)

$I=4.682(10)^{-22} \frac{kg}{mol} m^{2}$ (7)

Substituting (7) and (3) in (4):

$1.035 (10)^{-20} \frac{m^{2}kg}{s^{2}}=\frac{1}{2} (4.682(10)^{-22} \frac{kg}{mol} m^{2}) \omega^{2}$ (8)

Finding $\omega$ :

$\omega=6.65 rad/s$ (9) This is the average angular velocity for a molecule of O2

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3 years ago

A baseball goes from zero to 34 m/s in 0.188 s. What is its average acceleration? Answer in units of m/s^2

Kaylis [27]

Answer:

$a_{avg} = 180.85 m/s^{2}$

Given:

Initial velocity, u = 0 m/s

Final velocity, v = 34 m/s

Time interval, $\Delta t = 0.188 s$

Solution:

Acceleration is the rate at which the velocity of an object changes.

Thus

Average acceleration, $a_{avg} = \frac{\Delta v}{\Delta t}$

$a_{avg} = \frac{v - u}{t - 0} = \frac{34 - 0}{0.188} = 180.85 m/s^{2}$

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2 years ago

What is the charge on a hypothetical ion with 35 protons and 33 electrons?

kenny6666 [7]

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2 years ago

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Anna [14]

Answer:

Explanation:

Let the volume of the unknown bulb = X L

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3 years ago