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lozanna [386]
3 years ago
8

Where is the Grana located?

Biology
2 answers:
marta [7]3 years ago
8 0
The Grana is located in the Thylakoid. They are inside of a chloroplast cell in a plant. The correct answer is B.
eduard3 years ago
8 0
The grana is located in the B. Thylakoid.
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which specialized structures allow an adult amphibian to live on land and still maintain its internal balance
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The adults live on land for part of the time and breathe both through their skin and with their lungs. Adaptations for land in amphibians include protective skin and eyelids that allow them to adapt to vision outside of the water.
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Describe the process of natural selection
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Natural selection is the process in which the more favorable traits due to mutation that are in a select few in a population produce more offspring then others. An example of this is bacteria resistant to antibiotics due to the faster reproduction of the resistant bacteria over the non resistant ones
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stiv31 [10]

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<h2>The preying of one animal on others is predation. </h2>
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Why are only some plants sexually produced?​
Nadya [2.5K]

Answer:

Explanation:

This is because some plants grown by seeds which is as a result of fertilization or fusion of the male and female gametes. Seeds carries the genetic information. These sexual reproduction lead to formation of offsprings which have different genetic information from the parent or that are genetically different from the parent and these help them to survive or thrive and adapt in various environment.

4 0
3 years ago
An autosomal recessive disease has an incidence of 1/10,000. What is the approximate frequency of heterozygote carriers for this
goblinko [34]

Answer:

Option B

Explanation:

Given

Number of incidences or frequency of an autosomal recessive disease = \frac{1}{10000}

As per Hardy Weinberg's equation, frequency of a recessive genotype is q^{2}

q = \sqrt{\frac{1}{10000} }\\ q = \frac{1}{100}

As per first equation of Hardy Weinberg's -

p+q=1

so ,

p = 1-q\\p = 1-\frac{1}{100}\\p = \frac{99}{100}

p^2 = (\frac{99}{100})^2\\p^2 =\frac{9801}{1000}

As per second equation of Hardy Weinberg's -

p^{2} + q^{2} + 2pq=1

Substituting the given values in above equation, we get -

\frac{9801}{10000} + \frac{1}{100} + 2pq=1\\2pq = 1-(\frac{9801}{10000} + \frac{1}{100})\\2pq = 0.99%\\OR[tex]2pq=1%

2pq = \frac{1}{100}

Hence, option B is correct.

8 0
3 years ago
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