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Alja [10]
3 years ago
8

After constructing the circuit, Aliyah and Jeremy noticed that the light bulb stays on all the time. This means the batteries wi

ll get used up when the flashlight does not need to be on. What is something Aliyah and Jeremy can do to solve this problem?
Chemistry
1 answer:
Margarita [4]3 years ago
4 0

Answer: Implement a switch

Explanation:

This forms a circuit break or way to easily turn the flow of electricity on or off.

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An unknown gas Q requires 2.67 times as long to effuse under the same conditions as the same amount of nitrogen gas. What is the
Misha Larkins [42]

Answer:

The correct answer is 199.66 grams per mole.

Explanation:

Based on law of effusion given by Graham, a gas rate of effusion is contrariwise proportionate to the square root of molecular mass, that is, rate of effusion of gas is inversely proportional to the square root of mass. Therefore,  

R1/R2 = √ M2/√ M1

Here rate is the rate of effusion of the gas expressed in terms of number of mole per uni time or volume, and M is the molecular mass of the gas.  

Rate Q/Rate N2 = √M of N2/ √M of Q

The molecular mass of N2 or nitrogen gas is 28 grams per mole and M of Q is molecular mass of Q and based on the question Q needs 2.67 times more to effuse in comparison to nitrogen gas, therefore, rate of Q = rate of N2/2.67

Now putting the values we get,  

rate of N2/2.67/rate of N2 = √28/ √M of Q

√M of Q = √ 28 × 2.67

M of Q = (√ 28 × 2.67)²

M of Q = 199.66 grams per mole

3 0
3 years ago
Which part of the cell controls many functions of the cell and stores DNA?
kari74 [83]

Answer:

The Nucleus...

it perform many activities and stores DNA in a cell.

6 0
3 years ago
Read 2 more answers
The expected o-c-h angle in this molecule is degrees. the expected hybridization at the central carbon is
WINSTONCH [101]

Each neutral carbon atom contains four valence electrons and may form up to four electron domains. Possible hybridizations include

  • sp^{3}, four electron domains, as in ethane \text{C}_2\text{H}_6
  • sp^{2}, three electron domains, as in ethene \text{C}_2\text{H}_4
  • sp, two electron domains, as in ethyne \text{C}_2\text{H}_2

Molecules of each of the three hybridization demonstrate spatial configurations that would maximizes the separation between the electron domains.

  • Carbon atoms with a sp^{3} hybridization would demonstrate a tetrahedral configuration with a bond angle of approximately 109.5\textdegree{}
  • Carbon atoms with a sp^{2} hybridization would demonstrate a triangular planar configuration with a bond angle of 120\textdegree{}
  • Carbon atoms with a sp hybridization would demonstrate a linear configuration with a bond angle of 180\textdegree{}

Bond angles are characteristic of the spatial configuration of electron domains and identifies the hybridization of the central carbon atom.

Note that each hydrogen atom contains only one valence electron and would form only single bonds. It takes two valence electrons for oxygen atoms to achieve an octet such that each oxygen form only two bonds at a single time. Therefore given the fact that the carbon is bonded to both hydrogen and oxygen, only the following hybridizations are possible

  • sp^{3} in which the oxygen atom forms a carbon-oxygen double bond with the central carbon atom;
  • sp^{2} in which the oxygen atom forms a single bond with the central carbon atom and with a second atom.
3 0
3 years ago
Calculate the mass of oxygen in 30 g of CH NH COOH?​
Naya [18.7K]

Molar mass of CH2NH2COOH - 75

Given mass of CH2NH2COOH - 30

Moles of CH2NH2COOH = Given mass/ Molar mass

moles of CH2NH2COOH = 30/75 = 0.4 mol

One mole of CH2NH2COOH contains 32 gram of oxygen

0.4 mole of CH2NH2COOH will contain = 0.4 × 32= 12.8 g of oxygen

Answer- the mass of oxygen in 30 g of CH2NH2COOH is 12.8 gram!

7 0
2 years ago
The melting point of aluminum is about 660 °C. How many degrees above the boiling point of water is this temperature?
Arte-miy333 [17]
560 degrees above water
8 0
3 years ago
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