To determine the molar mass of the unknown gas, we use Graham's Law of Effusion where it relates the effusion rates of two gases with their molar masses. It is expressed as r1/r2 = √M2/M1. We calculate as follows:
Let 1 = argon gas
2 = unknown gas
r2 = 0.91r1
r1/r2 = 1/0.91
1/0.91 = √M2/M1 = √M2/40
M2 = 48.30 g/mol
Scene B depicts chemical change in matter at atomic change.
Composition distinguishes a chemical reaction from a physical reaction. In a chemical process, the makeup of the components changes; in a physical change, the appearance, smell, or straightforward exhibition of a sample of matter changes without changing its composition. Despite the fact that we refer to them as physical "reactions," nothing is actually changing. A change in the substance in question's elemental composition is necessary for a reaction to occur. Therefore, from now on, we will simply refer to bodily "reactions" as physical changes.
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The most common hydrogen carbon fuels are ethanol and diesel and their product of combustion is carbon dioxide, water and heat .
Answer:
0.02
Explanation:
To solve this problem we use the Boyle's law equation
P1V1 = P2V2
P1 = 76mmHg
V1 = 0.2L
P2 = 760mmHg
V2 = unknown
Substituting values into the equation;
76mmHg * 0.2L = 760mmHg * v2
15.2 = 760V2
Divide through by 760 to get v2
15.2/760 = 0.02
So the gas will occupy a volume of 0.02 at 760mmHg