Answer:
To prepare a 15L 0.920 % NaCl solution we need 138 grams of NaCL
Explanation:
Step 1: Data given
Normal saline is 0.920% (w/v)
⇒ 0.92 g NaCl / 100 mL H2O
Step 2: Calculate grams of NaCl needed to prepare 15 L
We need 0.92 grams of NaCl for 100 mL
We need 9.2 grams of NaCL for 1L
For 15L we need 9.2 grams * 15 = 138 grams of NaCl
To prepare a 15L 0.920 % NaCl solution we need 138 grams of NaCL
Answer:
speed = 16 kilometers per hour
= 16 km/h
Explanation:
Mark brainliest plssssss
the plant gets sunlight to make its food and grow. hope this helps a bit
Trihydrate - basically 3 molecules of water. Unless you're referring to the molecule 3H2O used in measuring the total body water in the case it tritiated water.