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AVprozaik [17]
3 years ago
10

Does the reaction of a main-group metal oxide in water produce an acidic solution or a basic solution? Write a balanced equation

for the reaction of a Group 2A(2) oxide with water.
Chemistry
1 answer:
Fynjy0 [20]3 years ago
4 0

<u>Answer:</u> The main group metal produce a basic solution in water and the reaction is MO+H_2O\rightarrow M(OH)_2

<u>Explanation:</u>

Main group elements are the elements that are present in s-block and p-block.

The metals that are the main group elements are located in Group IA, Group II A and Group III A.

Oxides are formed when a metal or a non-metal reacts with oxygen molecule. There are two types of oxides which are formed: Acidic oxides and basic oxides.

  • Acidic oxides are formed by the non-metals.
  • Basic oxides are formed by the metals.

When a metal oxide is reacted with water, it leads to the formation of a base.

The general formula of the oxide formed by Group II-A metals is 'MO'

The chemical equation for the reaction of metal oxide of Group II-A and water follows:

MO+H_2O\rightarrow M(OH)_2

Hence, the main group metal produce a basic solution in water and the reaction is MO+H_2O\rightarrow M(OH)_2

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Binary molecular compounds -- contain two or more nonmetals bonded covalently. There are no ions present because the atoms share electrons. Prefixes are used to indicate the number of atoms of each kind present. Examples are:
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The general formula for an acid is HX, where X is an anion. Binary acids contain H and a nonmetal and are named with the prefix "hydro" and the suffix "ic". Examples are:
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3 0
3 years ago
Hydrogen peroxide decomposes to form water and oxygen gas
EleoNora [17]
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3 years ago
What is the osmotic pressure of a solution made from 22.3 g of methanol (MM = 32.04 g/mol) that was added to water to make 321 m
xxMikexx [17]

Answer: The osmotic pressure of a solution is 53.05 atm

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (methanol) = 22.3 g  

Volume of solution = 321 mL

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

\pi=1\times \frac{22.3\times 1000}{32.04\times 321}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K

\pi=53.05atm

Hence, the osmotic pressure of a solution is 53.05 atm

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Hello,

A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.

Best regards.

6 0
3 years ago
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