1. 2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂
2. CH₄ + 2O₂ → CO₂ + 2H₂O
3. Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag
4. MnO₂ + 4HCl → MnCl₂ + 2H₂O + Cl₂
5. Pb(NO₃)₂ + 2NaCl → PbCl₂ + 2NaNO₃
1)

2)
CuSO_4+Cu_2Cl_2\neq>

Answer:
<h2>1.8662 × 10²⁴ atoms</h2>
Explanation:
The number of atoms can be found by using the formula
N = n × L
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
N = 3.1 × 6.02 × 10²³
We have the final answer as
<h3>1.8662 × 10²⁴ atoms</h3>
Hope this helps you
So what you do is you write out each element separately and how many of that element on either side of the arrow S-8|S-1
O-2|O-2
on one side theres 8 (S) and 2 (O) and 1(S) and 2(O) if you put a number in front to balance it you are multiplying it the elements number like
SO2 if I put a 2 in front now I will have 2(S) and 4(O)
Answer is 1,8,8
Answer:
The atomic mass of lead is: 207.216 u
Explanation:
data Isotopes mass percent
1 203.97302 1.4
2 205.974444 24.1
3 206.97587 22.1
4 207.97663 52.4
atomic mass = (203.97302x 0.014) + (205.974444 x 0.241) +
(206.97587 x 0.221) + (207.97663 x 0.524)
atomic mass = 2.856 +49.639 + 45.742 + 108.979
atomic mass = 207.216 u