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dezoksy [38]
2 years ago
9

The volume and amount of gas are constant in a tire. The initial pressure and temperature are 1.82 atm and 293 K. At what temper

ature will the gas in the tire have a pressure of 2.35 atm?
Chemistry
1 answer:
vladimir1956 [14]2 years ago
4 0

Answer:

When the pressure increases to 2.35 atm, the temperature will increase to 378 K

Explanation:

Step 1: Data given

The initial pressure = 1.82 atm

The initial temperature = 293 K

The pressure will be increased to 2.35 atm

Step 2: Calculate the new temperature

P1/T1 = P2/T2

⇒with P1 = the initial pressure = 1.82 atm

⇒with T1 = the initial temperature = 293 K

⇒with P2 = the increased pressure = 2.35 atm

⇒with T2 = the new temperature = TO BE DETERMINED

1.82atm / 293 K = 2.35 atm / T2

T2 = 2.35 atm / (1.82 atm/293 K)

T2 = 2.35 / 0.0062116

T2 = 378 K

When the pressure increases to 2.35 atm, the temperature will increase to 378 K

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An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark wit
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<u>Answer:</u> The molar mass of unknown triprotic acid is 97.66 g/mol

<u>Explanation:</u>

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of triprotic acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL

Putting values in above equation, we get:

3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 0.0077 M

Given mass of triprotic acid = 0.188 g

Volume of solution = 250 mL

Putting values in above equation, we get:

0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

7 0
2 years ago
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