1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dezoksy [38]
2 years ago
9

The volume and amount of gas are constant in a tire. The initial pressure and temperature are 1.82 atm and 293 K. At what temper

ature will the gas in the tire have a pressure of 2.35 atm?
Chemistry
1 answer:
vladimir1956 [14]2 years ago
4 0

Answer:

When the pressure increases to 2.35 atm, the temperature will increase to 378 K

Explanation:

Step 1: Data given

The initial pressure = 1.82 atm

The initial temperature = 293 K

The pressure will be increased to 2.35 atm

Step 2: Calculate the new temperature

P1/T1 = P2/T2

⇒with P1 = the initial pressure = 1.82 atm

⇒with T1 = the initial temperature = 293 K

⇒with P2 = the increased pressure = 2.35 atm

⇒with T2 = the new temperature = TO BE DETERMINED

1.82atm / 293 K = 2.35 atm / T2

T2 = 2.35 atm / (1.82 atm/293 K)

T2 = 2.35 / 0.0062116

T2 = 378 K

When the pressure increases to 2.35 atm, the temperature will increase to 378 K

You might be interested in
How many grams of agarose would you add to make 50ml of a 2 percent gel? why?
vodka [1.7K]
About 1 gram. 1 part of 50 is 2%
8 0
3 years ago
uyty7trrhgr sjkrvhvdvhv idlhasg iaiosg sidrug iowyhg eiroygiyega riyh aeoirgv aeyg reioaaioeyr goirfoiyer goiag oare5iphq vouptr
Vilka [71]

Answer:

what does this mean lol

Explanation:

?

6 0
3 years ago
How much heat was transferred from 50.0 g of water if the temperature of the water went from 30.0 ° C to 55.0 °? The specific he
Lena [83]

Answer:

Heat transfer = Q = 62341.6 J

Explanation:

Given data:

Heat transfer = ?

Mass of water = 50.0 g

Initial temperature = 30.0°C

Final temperature = 55.0°C

Specific heat capacity of water = 4.184 J/g.K

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 55.0°C -  30.0°C

ΔT = 25°C (25+273= 298 K)

Q = 50.0 g × 4.184 J/g.K ×298 K

Q = 62341.6 J

4 0
3 years ago
How many milliliters of 0.0630 m edta are required to react with 50.0 ml of 0.0110 m cu2 ?
gizmo_the_mogwai [7]
Moles Cu+2 = M * V
                     =  0.05 L * 0.011  m
                     = 0.00055 moles

when the molar ratio of Cu2+: EDTA = 1:1 so moles od EDTa also =0.00055 moles

and when the Molarity of EDTa = 0.0630 M

∴ Volume of EDTA =  moles / Molarity
                 = 0.00055 / 0.0630
                 = 0.0087 L = 8.7 L
4 0
3 years ago
A Bronsted- Lowry base
kari74 [83]
A bronsted lowry base will react to accept protons
3 0
3 years ago
Read 2 more answers
Other questions:
  • The testable question in a science investigation reads: “How does the size of a motor affect the speed of the vehicle?” What is
    7·1 answer
  • Which description is not a property of an acid?
    13·2 answers
  • 200 ml of a 0.500 m ca(no3)2 solution was made, but only 150 ml of solution are needed. if you pour out 50 ml of the soultion, w
    14·1 answer
  • Describe how magnetic forces and electric forces are similar and different from each other
    15·1 answer
  • What volume will 2.50 mol of hydrogen (H2) occupy at -20.0 °C and 1.5 atm?
    13·1 answer
  • A sodium hydroxide solution is made by mixing 8.70 g NaOH with 100 g of water. The resulting solution has a density of 1.087 g/m
    8·1 answer
  • What is the dependent variable for "how does changing your laundry detergent affect how clean your clothes are?"
    12·1 answer
  • Which are bundles of cells in the lungs that take in oxygen?
    10·1 answer
  • How much water must be added to 15 ml of a 2.5 M solution of sodium chloride to make a 2.0 M solution of sodium chloride?
    9·1 answer
  • A sample of hydrogen gas will behave most like an ideal gas under the conditions of
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!