To help you answer this question, you can search a sample reaction in the internet for hydroboration-oxidation. Take a look at the attached picture. The sample reaction is shown at the top. We can deduce that the original compound must be an alkene. Following the pattern, compound a must be 2-methylbutene as shown in the picture.
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I’m not sure but I’m sure it’s b please thank me
Answer:
8.25 moles
Explanation:
Given parameters:
Number of moles of Al produced = 11 moles
Unknown:
Number of moles of oxygen produced = ?
Solution:
To solve this problem, we need to understand the problem.
The decomposition of an aluminium oxide must has produced oxygen and aluminium,
2Al₂O₃ → 4Al + 3O₂
now since the known is the oxygen gas; we can find the unknown aluminium:
3 mole of O₂ was produced with 4 mole of Al
x mole of O₂ will be produced with 11 moles of Al
x = 
= 8.25 moles
Answer:
4.00L
Explanation:
Using Charle's law, which have the following equation:
V1/T1 = V2/T2
Where;
V1 = initial volume (litres)
T1 = initial temperature (Kelvin)
V2 = final volume (litres)
T2 = final temperature (Kelvin)
According to the information provided, T1 = 275K, T2 = 400K, V1 = ?, V2 = 5.82L
Hence, using the formula;
V1/275 = 5.82/400
400 × V1 = 275 × 5.82
400V1 = 1600.5
V1 = 1600.5 ÷ 400
V1 = 4.001
Therefore, volume of the gas before it is heated is 4.00L
