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Luba_88 [7]
4 years ago
13

As water is cooled from 4°C to 0° C, its density

Chemistry
1 answer:
Juliette [100K]4 years ago
8 0

Answer:

Option B - Density increases

Explanation:

Density is defined as:

δ = mass / volume

When T°2 is > T°1, volume has been increased

As the volume increased, density has decreased.

↓δ = mass / volume ↑

In the situation above, temperature decreased from 4° to 0°.

The volume has been reduced, so the density has been increased.

↑ δ = mass / volume ↓

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How many grams of NaCl is needed to make 750mL of a 2.4 M NaCl solution?
Aleksandr [31]

Answer:

Molarity of the solution = 3.000 M

Volume of the solution = 250.0 mL = 0.25 L

moles in 250.0 mL = molarity x volume of the solution

                             = 3.000 M x 0.25 L

                             = 0.75 mol

Hence, 0.75 mol of NaCl is needed to prepare 250.0 mL of 3.000 M NaCl solution.

Moles (mol) = mass (g) / molar mass (g/mol)

Moles of NaCl in 250.0 mL = 0.75 mol

Molar mass of NaCl           = 58.44 g/mol

Mass of NaCl in 250.0 mL = Moles x Molar mass

                                         = 0.75 mol x 58.44 g/mol

                                         = 43.83 g

Hence, 43.83 g of NaCl is needed to prepare 250.0 mL of 3.000 M solution.

Explanation:

6 0
3 years ago
The reaction described by H2(g)+I2(g)⟶2HI(g) has an experimentally determined rate law of rate=k[H2][I2] Some proposed mechanism
MatroZZZ [7]

Answer:

Mechanism A and B are consistent with observed rate law

Mechanism A is consistent with the observation of J. H. Sullivan

Explanation:

In a mechanism of a reaction, the rate is determinated by the slow step of the mechanism.

In the proposed mechanisms:

Mechanism A

(1) H2(g)+I2(g)→2HI(g)(one-step reaction)

Mechanism B

(1) I2(g)⇄2I(g)(fast, equilibrium)

(2) H2(g)+2I(g)→2HI(g) (slow)

Mechanism C

(1) I2(g) ⇄ 2I(g)(fast, equilibrium)

(2) I(g)+H2(g) ⇄ HI(g)+H(g) (slow)

(3) H(g)+I(g)→HI(g) (fast)

The rate laws are:

A: rate = k₁ [H2] [I2]

B: rate = k₂ [H2] [I]²

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]

<em>Where K' = K1 * K2</em>

C: rate = k₁ [H2] [I]

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]^1/2

Thus, just <em>mechanism A and B are consistent with observed rate law</em>

In the equilibrium of B, you can see the I-I bond is broken in a fast equilibrium (That means the rupture of the bond is not a determinating step in the reaction), but in mechanism A, the fast rupture of I-I bond could increase in a big way the rate of the reaction. Thus, just <em>mechanism A is consistent with the observation of J. H. Sullivan</em>

5 0
4 years ago
10. i really really need help plz don't waste time, thx :)
egoroff_w [7]
Lollll lollll lolll lolll
6 0
3 years ago
Read 2 more answers
Plant A gets no fertilizer, plnt B-5mg/day, and plnt C-10mg/day. Which is the control group?
prisoha [69]

Answer:

Plant A

Explanation:

This is because Plant A is what you will compare to the other plants. Because it has no fertilizer is is the independent variable.

8 0
3 years ago
Number 14 please help.. chemistry
Zolol [24]

Taking into account the definition of density, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Mass of the substance in this case</h3>

In this case, you know that:

  • Density= 1.5 \frac{g}{cm^{3} }
  • Volume= 150 cm³

Replacing in the definition of density:

1.5 \frac{g}{cm^{3} } =\frac{mass}{150 cm^{3} }

Solving:

mass= 1.5 \frac{g}{cm^{3} }  ×150 cm³

<u><em>mass= 225 g</em></u>

In summary, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

Learn more about density:

brainly.com/question/952755

brainly.com/question/1462554

#SPJ1

7 0
2 years ago
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