Answer:
Determining whether a ladybug is male or female has nothing to do with the size or number of black spots on the insect's orange body. Both sexes have these spots. The male is generally slightly smaller than the female. The ladybug's reproductive organs share the abdomen, along with the digestive and respiratory organs.
Explanation:
The scientists would do biological studies of how the protein breakdown and combines with the muscles the engineers with then create a delivery system to get the protein to the muscle quicker and more effectively
Answer:
Final T = 64.0°C.
Explanation:
- The amount of heat absorbed by Na (Q) can be calculated from the relation:
<em>Q = m.c.ΔT.</em>
where, Q is the amount of heat absorbed by Na (Q = 1840 J),
m is the mass of Na (m = 68.0 g),
c is the specific heat capacity of Na (c = 1.23 J/g °C),
ΔT is the temperature difference (final T - initial T) (ΔT = final T - 42.0°C).
∵ Q = m.c.ΔT.
∴ (1840 J) = (68.0 g)(1.23 J/g °C)(final T - 42.0°C)
(final T - 42.0°C) = (1840 J)/(68.0 g)(1.23 J/g °C) = 22.0°C.
<em>∴ final T</em> = 22.0°C + 42.0°C = <em>64.0°C.</em>
Answer:
4.74
Explanation:
It is possible to find pH of a buffer (The mixture of a weak acid: Acetic acid, with its conjugate base: Sodium acetate) using Henderson-Hasselbalch equation:
pH = pKa + log₁₀ [A⁻] / [HA]
<em>Where pKa is -log Ka of the weak acid, [A⁻] concentration of the conjugate base and [HA] concentration of the weak acid</em>
pKa of acetic acid is -log 1.8x10⁻⁵ = 4.74
The concentration of both, acetic acid and sodium acetate is 0.1M. Replacing in H-H equation:
pH = pKa + log₁₀ [A⁻] / [HA]
pH = 4.74 + log₁₀ [0.1] / [0.1]
pH = 4.74 + log₁₀ 1
<em>pH = 4.74</em>
Theoretical pH is 4.74
<em />
