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3 years ago

Scientific laws explain_____.

Physics

1 answer:

arsen [322]3 years ago

3 0

Howdy! I have your answer:

Scientific laws explain repeated observations that are experimental.

It also describes aspects of the universe.

~sofia

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How does newton's second law describe the motion of an object?

vodomira [7]

Answer:

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Explanation:

4 0

3 years ago

Read 2 more answers

Find velocity vx(t) and coordinate x(t) for a particle of mass m which is subject to the force given by: Fx = F0 e −kt , where F

muminat

Answer:

$v_{x} (t)=1+\frac{ F_{0}}{km}(1-e^{-kt})$

$x=t+\frac{ F_{0}t}{km}+\frac{ F_{0}t}{k^{2} m}(e^{-kt}-1)$

Explanation:

Given that the force of the particle is,

$F_{x}=F_{0}e^{-kt}$

Now it can be further written as

$m\frac{dv}{dt}= F_{0}e^{-kt}\\\frac{dv}{dt}=\frac{ F_{0}}{m} e^{-kt}\\dv=\frac{ F_{0}}{m}e^{-kt}dt\\ v=\frac{ F_{0}}{-km}e^{-kt}+C$

Now the initial conditions are v=1 at t=0.

So,

$1=\frac{ F_{0}}{-km}e^{0}+C\\C=1+\frac{ F_{0}}{km}$

Now the velocity will become.

$v_{x} (t)=\frac{ F_{0}}{-km}e^{-kt}+1+\frac{ F_{0}}{km}\\v_{x} (t)=1+\frac{ F_{0}}{km}(1-e^{-kt})$

And,

$\frac{dx}{dt} =1+\frac{ F_{0}}{km}(1-e^{-kt})\\dx=(1+\frac{ F_{0}}{km}(1-e^{-kt}))dt\\x=t+\frac{ F_{0}t}{km}+\frac{ F_{0}t}{k^{2} m}e^{-kt}+C\\$

And, another initial condition is x=0 at t=0

$0=0+\frac{ F_{0}0}{km}+\frac{ F_{0}t}{k^{2} m}e^{0}+C\\C=-\frac{ F_{0}t}{k^{2} m}$

Now,

$x=t+\frac{ F_{0}t}{km}+\frac{ F_{0}t}{k^{2} m}e^{-kt}+-\frac{ F_{0}t}{k^{2} m}\\x=t+\frac{ F_{0}t}{km}+\frac{ F_{0}t}{k^{2} m}(e^{-kt}-1)$

5 0

3 years ago

Which of the following is/are true of a vector? Check all that apply.

AfilCa [17]

Answer:

Explanation:

4 0

3 years ago

Consider a cylinder initially filled with 9.33 10-4 m3 of ideal gas at atmospheric pressure. An external force is applied to slo

Juli2301 [7.4K]

Answer:

Work done will be 78.76 J

Explanation:

We have given initial volume of the gas $V_1=9.33\times 10^{-4}m^3$

Pressure is given by $P=1.013\times 10^5Pa$

Final volume $V_2=\frac{V_1}{6}=\frac{9.33\times 10^{-4}}{6}=1.555\times 10^{-4}m^3$

Change in volume $\Delta V=V_2-V_1=1.555\times 10^{-4}-9.33\times 10^{-4}=-7.775\times 10^{-4}m^3$

We know that work done is given by

$W=-Pdv=-1.013\times 10^5\times 7.775\times 10^{-4}=78.760J$

Work done will be 78.76 J

8 0

3 years ago

Wanda exerts a constant tension force of 12 N on an essentially massless string to keep a tennis ball (m = 60 g) attached to the

goldfiish [28.3K]

Answer:

r = 0.405m = 40.5cm

Explanation:

In order to calculate the length of the string between Wanda and the ball, you take into account that the tension force is equal to the centripetal force over the ball. So, you can use the following formula:

$F_c=ma_c=m\frac{v^2}{r}$ (1)

Fc: centripetal acceleration (tension force on the string) = 12N

m: mass of the ball = 60g = 0.06kg

r: length of the string = ?

v: linear speed of the ball = 9.0m/s

You solve for r in the equation (1) and replace the values of the other parameters:

$r=\frac{mv^2}{F_c}=\frac{(0.06kg)(9.0m/s)^2}{12N}=0.405m$

The length of the string between Wanda and the ball is 0.405m = 40.5cm

7 0

3 years ago