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4 years ago

How many different groups of 6 shirts can be formed from 10 shirts for a display

2 answers:

6 0

I believe the shirts are different (in color, in size, in style,...), is so then:

¹⁰C₆ = (10! )/( 6! )( 10-6) ! = 210 COMBBINATIONS

OverLord2011 [107]4 years ago

3 0

10C6 = 210 combinations

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Answer Is not C please help

Katyanochek1 [597]

Answer:

Step-by-step explanation:

Well since it is arthimetic sequence we know the formula

We know d is difference between second term and first so it will be -5- (-12)= -5+12= 7

$a_{n}= a _{1}+ d (n-1) \\a_{n}= -12+7(n-1)\\a_{n} = -12+7n-7\\a_{n}= 7n-19$

the domain of this is 1,2,3,4.......

range is -12,-5,2,9.......

Therefore answer is B.

5 0

3 years ago

Rectangle LMNO is similar to rectangle PQRS. What is the length of segment QP?

kherson [118]

29.75/8.5=x/4.5
using the "butterfly method"
8.5x=133.875
/8.5 /8.5
x=15.75

You have to make a proportion

6 0

3 years ago

Type an equation for the line shown in the graph

natulia [17]

0x+2 =y
So technically x+2=y

4 0

3 years ago

Sarah and noah work at read on bookstore and get paid the same hourly wage.

vitfil [10]

So whats the question or you stating a statement.

7 0

3 years ago

You wish to compare the prices of apartments in two neighboring towns. You take a simple random sample of 12 apartments in town

Rom4ik [11]

Answer:

The value of P-value is 0.0472.

Step-by-step explanation:

We are given that you take a simple random sample of 12 apartments in town A and calculate the average price of these apartments. You repeat this for 15 apartments in town B.

Let $\mu_1$ = true average price of apartments in town A

$\mu_2$ = true average price of apartments in town B

So, Null Hypothesis, $H_0$ : $\mu_1=\mu_2$

Alternate Hypothesis, $H_A$ : $\mu_1\neq \mu_2$

The test statistics that have been used here is two-sample t-test statistics, i.e;

The test statistics given to us is 2.1

Now, the P-value of the test statistics is given by the following formula;

P-value = P( $t__n__1+_n_2-_2$ > 2.1)

= P( $t_2_5$ > 2.1) = 0.0236

In two-tailed test, P-value is calculated as = 2 $\times$ 0.0236 = 0.0472

Hence, the value of the p-value is 0.0472.

7 0

3 years ago