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Ugo [173]
3 years ago
12

What is the name of the process that is responsible for the formation of elements heavier than hydrogen? A) fusion B) fission C)

implosion D) gamma decay
Physics
1 answer:
gladu [14]3 years ago
5 0

Answer:

A) Fusion

Explanation:

Fusions of atoms heavier than hydrogen like helium takes place in the core of the star, at the core the temperature and density of gases is the greatest .

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The first law of motion is also called as law _ fill up the blanks ​
Roman55 [17]

Answer:

law of inertial

Explanation:

state that if anobject is in motion it will continue to move until some external force act on it.

5 0
3 years ago
What is the main source of groundwater? A. precipitation falling into man-made wells B. precipitation seeping through pores and
Yuliya22 [10]

Answer:

B: precipitation seeping through pores and cracks in the ground

Explanation:

Man made wells aren't the main source because their isn't enough of them and morning dew doesn't go in to the ground in one main source.

5 0
3 years ago
A car accelerates from rest. It reaches a velocity of 25m/s in 10 seconds. What was the cars acceleration
soldier1979 [14.2K]

Answer:

a = 2.5 m/s^2

Explanation:

u = 0

v = 25

t = 10

(using first eq. of motion)

a = (v - u) /t

a = (25 - 0) /10

a = 25/10

a = 2.5 m/s^2

7 0
3 years ago
1.20 Newton force is working on a 250 gram object. What is the acceleration?
Leokris [45]

Answer:

The answer is B

Explanation:

250g = 0.25kg

F = m × a

a = F/m

= 1.2/0.25

= 4.8m/s²

7 0
3 years ago
The moment of inertia of a thin ring of mass M and radius R about its symmetry axis is ICM = MR2.
monitta

Answer:

The moment of inertia of large ring is 2MR².

(A) is correct option.

Explanation:

Given that,

Mass of ring = M

Radius of ring = R

Moment of inertia of a thin ring = MR²

Moment of inertia :

Moment of inertia is the product of the mass of the ring and square of radius of the ring.

We need to calculate the moment of inertia of large ring

Using formula of moment of inertia

I=I_{cm}+MR^2

Where, I_{cm} = moment of inertia at center of mass

M = mass of ring

R = radius of ring

Put the value into the formula

I=MR^2+MR^2

I=2MR^2

Hence, The moment of inertia of large ring is 2MR².

6 0
3 years ago
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