How many electrons can the 4d orbitals have all together?

For the reaction C6H14(g) ------> C6H6(g) + 4H2(g), the rate of formation of hydrogen gas, H2 was found to be 2.5 x 10-2 atm/

riadik2000 [5.3K]

Answer : The rate of consumption of hexane is, $6.25\times 10^{-3}atm/s$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$C_6H_{14}(g)\rightarrow C_6H_6(g)+4H_2(g)$

The expression for rate of reaction :

$\text{Rate of disappearance of }C_6H_{14}=-\frac{d[C_6H_{14}]}{dt}$

$\text{Rate of formation of }C_6H_6=+\frac{d[C_6H_6]}{dt}$

$\text{Rate of formation of }H_2=+\frac{1}{4}\frac{d[H_2]}{dt}$

As we know that, the partial pressure is directly proportional to the concentration. So,

$\text{Rate of reaction}=-\frac{dP_{C_6H_{14}}}{dt}=+\frac{dP_{C_6H_6}}{dt}=+\frac{1}{4}\frac{dP_{H_2}}{dt}$

Given:

$+\frac{dP_{H_2}}{dt}=2.5\times 10^{-2}atm/s$

As,

$-\frac{dP_{C_6H_{14}}}{dt}=+\frac{1}{4}\frac{dP_{H_2}}{dt}=2.5\times 10^{-2}atm/s$

and,

$\frac{dP_{C_6H_{14}}}{dt}=\frac{1}{4}\times 2.5\times 10^{-2}atm/s$

$\frac{dP_{C_6H_{14}}}{dt}=6.25\times 10^{-3}atm/s$

Thus, the rate of consumption of hexane is, $6.25\times 10^{-3}atm/s$

4 0

4 years ago

A microscope containing two or more lenses is an

kicyunya [14]

<span> A compound <span>lens microscope. </span></span>

6 0

3 years ago

Dominic and Eva are using the same type of stopwatches to measure the time it takes for a chemical reaction to occur. They each

SIZIF [17.4K]

They did not repeat their tests multiple times.

Reason being is using the same stopwatch doesn’t matter and changing the reactants won’t help, and you without a doubt need more than one person collecting the data so,

They did not repeat their tests multiple times is the answer.

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2 years ago

A topaz crystal has an interplanar spacing (d) of 1.36 Å (1 Å =1×10^[−10] m). Calculate the wavelength of the X-ray that should

bija089 [108]

Answer:

7.0*10-11m or 70Å

Explanation:

From Bragg's equation, w=2dsinx/n

Since all the parameters are specified in the question, we can easily go ahead to obtain the wavelength but we must convert the spacing given in angstroms to meters using the conversion factor provided as shown in the solution below:

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Given the following reaction:

fredd [130]

Answer:D. In order to restore equilibrium, the reaction shifts right, towards products

Explanation:

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2 years ago