Answer:
Josue
Explanation:
J.J Thompson proposed the plum pudding model of the atom. In his proposition, the atom is a sphere of positive charges into which negative charges were embedded. This model of the atom did not significantly contribute to our present day understanding of atomic structure.
On the other hand Ernest Rutherford laid out the foundation for a more accurate understanding of atomic structure in his nuclear model of the atom. According to Rutherford, the atom consists of a positively charged massive core called the nucleus around which electron move in orbits. His idea was akin to the solar system with the sun at it's core and planets moving around the sun in orbits.
This his idea of the nuclear theory was held as fundamentally correct by Neils Bohr's model of the atom. Hence, his nuclear theory of the atom was a significant milestone in our present day understanding of atomic structure.
The question is incomplete, here is the complete question:
Calculate the pH at of a 0.10 M solution of anilinium chloride 
. Note that aniline 
is a weak base with a 
of 4.87. Round your answer to 1 decimal place.
<u>Answer:</u> The pH of the solution is 5.1
<u>Explanation:</u>
Anilinium chloride is the salt formed by the combination of a weak base (aniline) and a strong acid (HCl).
To calculate the pH of the solution, we use the equation:
![pH=7-\frac{1}{2}[pK_b+\log C]](https://tex.z-dn.net/?f=pH%3D7-%5Cfrac%7B1%7D%7B2%7D%5BpK_b%2B%5Clog%20C%5D)
where,
= negative logarithm of weak base which is aniline = 4.87
C = concentration of the salt = 0.10 M
Putting values in above equation, we get:
![pH=7-\frac{1}{2}[4.87+\log (0.10)]\\\\pH=5.06=5.1](https://tex.z-dn.net/?f=pH%3D7-%5Cfrac%7B1%7D%7B2%7D%5B4.87%2B%5Clog%20%280.10%29%5D%5C%5C%5C%5CpH%3D5.06%3D5.1)
Hence, the pH of the solution is 5.1
Answer:
8.75 g of ZnO
Solution:
The Balance Chemical Reaction is as follow,
2 ZnS + 3 O₂ → 2 ZnO + 2 SO₂
Step 1: Find out the limiting reagent as;
According to Equation ,
194.94 g (2 mole) ZnS reacts with = 96 g (3 moles) of O₂
So,
12.85 g of ZnS will react with = X g of O₂
Solving for X,
X = (12.85 g × 96 g) ÷ 194.94 g
X = 6.32 g of O₂
It means for total utilization of 12.85 g of ZnS we require 6.32 g of O₂, but we are provided with 15.91 g of O₂. Therefore, ZnS is the limiting reagent and will control the yield.
Step 2: Calculate Amount of ZnO produced as;
According to Equation ,
194.94 g (2 mole) ZnS produces = 132.81 g (2 moles) of ZnO
So,
12.85 g of ZnS will produce = X g of ZnO
Solving for X,
X = (12.85 g × 132.81 g) ÷ 194.94 g
X = 8.75 g of ZnO
The formula for nickel (III) sulfide is Ni3S2
