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3 years ago

What are some ways in which companies can attract and retain employees? (site 2)

Mathematics

2 answers:

slava [35]3 years ago

7 0

The company can offer a variety of benefits not inly for the employee but also for the family.

Stolb23 [73]3 years ago

3 0

Answer:

Step-by-step explanation:

There are various ways in which companies can attract and retain employees

This is important because labor turnover requires additional expenses of recruitment, and training to the new persons, etc.

The existing skilled persons can be retained by

i) Creating a pleasant atmosphere in the office to work

ii) Increasing promotional opportunities and increments

iii) Protecting employees whenever any lapse or mistake happens unintentionally

iv) Giving lunch subsidy and other perquisites

v) Extending support to children education, medical expenses of families etc.

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Please help I need due ....

seropon [69]

Answer:

The answer is 22 2/5

Step-by-step explanation:

So the correct is B

6 0

2 years ago

A bank account earns interest at a rate of 3.5% per year ( in other words it increases in value by that percent) and starts with

LenKa [72]

Annually cumulating interest can be determined by the following formula:

$W = P(1+r)^{y}$

r represents the interest rate as a decimal, and P represents the starting amount of money.

8 0

3 years ago

A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s

yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

$x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2} = \frac{1 \pm 9 }{-0.4}$

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0

3 years ago

Y-3=2(x+1)<br> Can you guys please help me solve for y

Tatiana [17]

Answer:

First, you have to rewrite the question in a way to isolate your Y. This means moving the -3 over to the other side.

Y = 2(x+1) + 3

Now, you should multiply the 2 out in the parenthesis.

Y=2x+2+3

Now, combine like terms! In this case, your like terms are 2 and 3.

Y=2x + 5

Because there are no more like terms, and Y is completely isolated, Y=2x + 5 is your answer!

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E4_3%7Bx%5E%7B2%7D-x%20%7D%20%5C%2C%20dx" id="TexFormula1" title="\int\limits

melisa1 [442]

Answer:

$\frac{53}{6}$

Step-by-step explanation:

$\int\limits^4_3 {x^2-x} \, dx$

= [ $\frac{x^3}{3}$ - $\frac{x^2}{2}$ ] ← evaluate for upper limit - lower limit

= ( $\frac{64}{3}$ - $\frac{16}{2}$ ) - ( $\frac{27}{3}$ - $\frac{9}{2}$ )

= $\frac{64}{3}$ - 8 - 9 + $\frac{9}{2}$

= $\frac{155}{6}$ - 17

= $\frac{53}{6}$

5 0

3 years ago