Answer:
Explanation:
S orbital has a spherical shape
P orbital has a dumb-bell shape
d orbital has a double dumb-bell shape
Answer:
2 electrons
E. neon
Explanation:
Metals lose electrons under certain conditions to attain a noble gas electron configuration. Magnesium has 12 electrons and its electron configuration is
1s² 2s² 2p6⁶ 3s²
When magnesium loses 2 electrons, it acquires the electron configuration of neon (10 electrons).
Data:
<span>Solute: 28.5 g of glycerin (C3H8O3)
Solvent: 135 g of water at 343 k.
Vapor pressure of water at 343 k: 233.7 torr.
Quesiton: Vapor pressure of water
Solution:
Raoult's Law: </span><span><span>The vapour
pressure of a solution of a non-volatile solute is equal to the vapour
pressure of the pure solvent at that temperature multiplied by its mole
fraction.
Formula: p = Xsolvent * P pure solvent
X solvent = moles solvent / moles of solution
molar mass of H2O = 2*1.0g/mol + 16.0 g/mol = 18.0 g/mol
moles of solvent = 135 g of water / 18.0 g/mol = 7.50 mol
molar mass of C3H8O3 = 3*12.0 g/mol + 8*1 g/mol + 3*16g/mol = 92 g/mol
moles of solute = 28.5 g / 92.0 g/mol = 0.310 mol
moles of solution = moles of solute + moles of solvent = 7.50mol + 0.310mol = 7.810 mol
Xsolvent = 7.50mol / 7.81mol = 0.960
p = 233.7 torr * 0.960 = 224.4 torr
Answer: 224.4 torr
</span> </span>
Answer:
The answer to your question is Volume = 0.7 l
Explanation:
Data
Volume 1 = V1 = 0.746 l
Pressure 1 = P1 = 94.6 kPa
Volume 2 = V2 = ?
Pressure 2 = 101.33 kPa
Process
To solve this process use Boyle's law.
P1V1 = P2V2
-Solve for V2
V2 = P1V1/P2
-Substitution
V2 = (94.6 x 0.746) / 101.33
-Simplification
V2 = 70.57 / 101.33
-Result
V2 = 0.696 l ≈ 0.7 l
