To find the empirical formula you would first need to find the moles of each element:
58.8g/ 12.0g = 4.9 mol C
9.9g/ 1.0g = 9.9 mol H
31.4g/ 16.0g = 1.96 O
Then you divide by the smallest number of moles of each:
4.9/1.96 = 2.5
9.9/1.96 = 6
1.96/1.96 = 1
Since there is 2.5, you find the least number that makes each moles a whole number which is 2.
So the empirical formula is C5H12O2.
Answer:
Al + 4AgNO3 >>Al(NO3)3+ 3Ag
Explanation:
the number of moles of No3 of the products is 3 therefore we have to balance the reactants by adding 3 before the "AgNO3" which also leades us to adding 3 mols to Ag on the products side
Hey there!
The elements in this equation are K, N, O, H, and C.
Let's count how many of each are on each side to see if it is balanced.
K: 2 on the left, 2 on the right.
<em>N: 2 on the left, 4 on the right. </em>
<em>O: 9 on the left, 6 on the right. </em>
<em>H: 2 on the left, 4 on the right. </em>
C: 1 on the left, 1 on the right.
Notice that there are different amounts of N, O, and H on the left side and the right side.
This means that the equation is not balanced.
Hope this helps!
