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Vaselesa [24]
2 years ago
10

In order to prepare very dilute solutions, a lab technician chooses to perform a series of dilutions instead of measuring a very

small mass. A solution was prepared by dissolving 0.360 g of KNO3 in enough water to make 500. mL of solution. A 10.0 mL sample of this solution was transferred to a 500.0-mL volumetric flask and diluted to the mark with water. Then 10.0 mL of the diluted solution was transferred to a 250.0-mL flask and diluted to the mark with water. What is the final concentration of the KNO3 solution?
7.91 × 10-9 M
5.70 × 10-6 M
2.85 × 10-6 M
7.12 × 10-3 M
1.42 × 10-4 M
Chemistry
1 answer:
laiz [17]2 years ago
8 0

Answerit is a

Explanation:

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Helpppppp i hate chemistry
BigorU [14]

Answer:

The first option: Strontium Fluorate.

Explanation:

because Fluorine and oxygen combines to make fluorate, Strontium stays the same.

p.s: i need help in geo and there's an exam tomorrow.

8 0
3 years ago
The hydrochloride form of cocaine has a solubility of 1.00 g in 0.400 mL water. Calculate the molarity of a saturated solution o
Tanya [424]

Answer:

The molarity of the solution is 7.4 mol/L

Explanation:

From the question above

0.400 ml of water contains 1.00 g of hydrochloride form of cocaine

Therefore 1000 ml of water will contain x g of hydrochloride form of cocaine

                    x = 1000 / 0.400

                    x = 2500 g

2500g of hydrochloride form of cocaine is present in 1000 ml of water.

Mole of hydrochloride form of cocaine = mass /molar mass of hydrochloride

Mole of hydrochloride form of cocaine = 2500/339.8

                                                                = 7.4 mol

Molarity = mol/ volume in liter (L)

molarity = 7.4 /1

Molarity = 7.4 mol/L

6 0
3 years ago
Read 2 more answers
Can you separate cooking oil from a mixture of cooking oil and water by filtering
slega [8]
Yes, they can be separated by using a funnel. In the separating funnel, they are kept for resting. After they are separated they are filtered one by one.
3 0
2 years ago
The temperature of a 100.0 g sample of water is raised from 30degrees celsius to 100.0 degrees celsius. How much energy is requi
worty [1.4K]

Answer:

29260J

Explanation:

Given parameters:

Mass of water sample  = 100g

Initial temperature = 30°C

Final temperature  = 100°C

Unknown:

Energy required for the temperature change = ?

Solution:

The amount of heat required for this temperature change can be derived from the expression below;

     H  = m c (ΔT)

H is the amount of heat energy

m is the mass

c is the specific heat capacity of water  = 4.18J/g°C

ΔT is the change in temperature

Now insert the parameters and solve;

          H  = 100 x 4.18 x (100 - 30)

          H  = 100 x 4.18 x 70 = 29260J

6 0
2 years ago
If you have 1.00 mole of F2 at 1.00 atm of pressure and 0°C, what is the volume of F2?
ss7ja [257]

Answer:

V=22.4L

Explanation:

Hello,

In this case, by using the ideal gas equation, er can compute the volume of fluorine gas as shown below:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1mol*0.082\frac{atm*L}{mol*K}+(0+273)K}{1.00atm}  \\\\V=22.4L

Best regards.

4 0
2 years ago
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